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Alex787 [66]
2 years ago
5

An object that is magnetic all of the time is called a.

Physics
1 answer:
Novosadov [1.4K]2 years ago
5 0

Answer:

Bar magnets are permanent magnets. This means that their magnetism is there all the time and cannot be turned on or off as it can with electromagnets .

Explanation:

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Refraction occurs when a wave enters a new medium at an angle because
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The refracted wave must obey Snell's equation

Ni sin θi = Nr sin θr

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If the wave originates from point A and ends at point B then Snell's Law shows that the time for light to get from point A to point B is a minimum.

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3 years ago
How do I solve this problem?<br> Can someone please help?
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Which were difficulties that the builders of the transcontinental railroad found ways to overcome? Select all the choices that apply.


Answer: Out of all the options presented above the ones that represent the difficulties that the builders of the transcontinental railroad found ways to overcome are answer choices A) providing supplies to build the tracks and support the workers and B) natural barriers such as mountains, rivers, and forests. It was also the same reason why the transcontinental railroad was being constructed. It would help the transportation of  if this is hitory i dont know what subject this is but if its history heres the answers

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3 years ago
Do you think climate change is affecting our seasons? Why or why not? Share the links you found that support your theory.
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6 0
4 years ago
According to the work equation, if you want to increase the distance on the
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3 years ago
Work and Energy
Sergeeva-Olga [200]

a) W_1 = 2332 J, W_2= 2332 J

The work done by the student in each trial is equal to the gravitational potential energy gained by the student:

W=mg\Delta h

where

m = 68 kg is the mass of the student

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h is the gain in height of the student

For the first student, \Delta h = 3.5 m, so the work done is

W_1 = (68)(9.8)(3.5)=2332 J

The second student runs up to the same height (3.5 m), so the work done by the second student is the same:

W_2 = (68)(9.8)(3.5)=2332 J

2) P_1 = 204.6 W, P_2 = 274.4 W

The power exerted by each student is given by

P=\frac{W}{t}

where

W is the work done

t is the time taken

For the first student, W_1 = 2332 J and t=11.4 s, so the power exerted is

P_1 = \frac{W_1}{t_1}=\frac{2332 J}{11.4 s}=204.6 W

For the second student, W_2 = 2332 J and t=8.5 s, so the power exerted is

P_2 = \frac{W_2}{t_2}=\frac{2332 J}{8.5 s}=274.4 W

5 0
3 years ago
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