An object is said to move from a position of 10m East to a position of 5m west. Determine the object's distance travelled.

Convertir 500 f a grado celsios

Allushta [10]

Answer:

260° C

Explanation:

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5 0

2 years ago

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A long, thin rod parallel to the y-axis is located at x = - 1 cm and carries a uniform positive charge density λ = 1 nC/m . A se

zheka24 [161]

Answer:

The electric field at origin is 3600 N/C

Solution:

As per the question:

Charge density of rod 1, $\lambda = 1\ nC = 1\times 10^{- 9}\ C$

Charge density of rod 2, $\lambda = - 1\ nC = - 1\times 10^{- 9}\ C$

Now,

To calculate the electric field at origin:

We know that the electric field due to a long rod is given by:

$\vec{E} = \frac{\lambda }{2\pi \epsilon_{o}{R}$

Also,

$\vec{E} = \frac{2K\lambda }{R}$ (1)

where

K = electrostatic constant = $\frac{1}{4\pi \epsilon_{o} R}$

R = Distance

$\lambda$ = linear charge density

Now,

In case, the charge is positive, the electric field is away from the rod and towards it if the charge is negative.

At x = - 1 cm = - 0.01 m:

Using eqn (1):

$\vec{E} = \frac{2\times 9\times 10^{9}\times 1\times 10^{- 9}}{0.01} = 1800\ N/C$

$\vec{E} = 1800\ N/C$ (towards)

Now, at x = 1 cm = 0.01 m :

Using eqn (1):

$\vec{E'} = \frac{2\times 9\times 10^{9}\times - 1\times 10^{- 9}}{0.01} = - 1800\ N/C$

$\vec{E'} = 1800\ N/C$ (towards)

Now, the total field at the origin is the sum of both the fields:

$\vec{E_{net}} = 1800 + 1800 = 3600\ N/C$

7 0

2 years ago

Does anyone want to join an LGBTQ squad?

Korvikt [17]

Mooooooooooooooooooo

6 0

2 years ago

What are the four components of a controlled experiment?. A. opinions, independent variable, constant, control. B. data that mat

kherson [118]

I believe the correct answer among the choices listed is option C. The four components of a controlled experiment are the independent variable, dependent variable, control, constant. A controlled experiment is a test where a researcher vary one variable at a time.<span>
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3 0

3 years ago

Jupiter's four large moons – Io, Europa, Ganymede, and Castillo – were discovered by Galileo in 1610. Jupiter also has dozens of

Maksim231197 [3]

Answer:

The orbital speed is approximately 17,325.57 m/s

The number of Earth days it would take lo to complete its orbit is approximately 1.77 days

Explanation:

The given parameters are;

The mass of lo, m ≈ 7.22 × 10²² kg

The radius of lo, R ≈ 1.82 × 10⁶ m

The mean distance between Jupiter and lo = 4.22 × 10⁸ m

The orbital equation is given as follows;

$\dfrac{m \cdot v^2}{R} = \dfrac{G \times M \times m}{R^2}$

$\therefore v = \sqrt{\dfrac{G \cdot M}{R} } = \sqrt{\dfrac{ 6.67408 \times 10^{-11} \times 1.898 \times 10^{27}}{4.22 \times 10^8} } = 17,325.57 \ m/s$

The orbital speed ≈ 17,325.57 m/s

The time to complete one orbit = (2 × π × 4.22 × 10⁸)/(17325.57) ≈ 153039.94 s

The time to complete one orbit ≈ 153039.94 s ≈ 1.77 days

The number of Earth days it would take lo to complete its orbit ≈ 1.77 days.

4 0

2 years ago