All categories

3 years ago

What is the formula for a simple sugar?

Physics

2 answers:

Brilliant_brown [7]3 years ago

7 0

Answer:

<em>The chemical formula of simple sugar is </em> $C_{6} H_{12} O_{6}$

Explanation:

<h3>Simple Sugars</h3>

Simple sugars are a group of carbohydrates that made up of single sugar molecule or two combined sugar molecules.

<h3>Monosaccharides </h3>

This is a type of single sugar that contains only one molecule of sugar. monosaccharides are classified as glucose, fructose, and galactose.

The three monosaccharides have $C_{6} H_{12} O_{6}$ as the chemical formulae but differ by their atom arrangement.

<h3>Disaccharide </h3>

Disaccharide is a type of simple sugar that is obtained when two monosaccharides combine. They are sometimes referred to as double single sugar. Maltose, sucrose, and lactose are examples of disaccharides.

Since the monosaccharides are the basic building block of all simple sugar, the basic simple sugar formula is that of the monosaccharides. Therefore, the formula for simple sugar is $C_{6} H_{12} O_{6}$

mina [271]3 years ago

3 0

<h3>c<em>6</em>h<em>12O6 this is the formula</em></h3>

You might be interested in

A 8.00g sample of substance (substance, molar mass = 152.0 g/mol) was combusted in a bomb calorimeter with a heat capacity of 6.

aleksandrvk [35]

Answer:

ΔH°comb=-5899.5 kJ/mol

Explanation:

First, consider the energy balance:

$m_{c} *Cp*(T_{2}-T_{1})=-n_{s} *H_{c}$ Where $m_{c}$ is the calorimeter mass and $n_{s}$ is the number of moles of the samples; $H_{c}$ is the combustion enthalpy. The energy balance says that the energy that the reaction release is employed in rise the temperature of the calorimeter, which is designed to be adiabatic, so it is suppose that the total energy is employed rising the calorimeter temperature.

The product $m_{c} *Cp$ is the heat capacity, so the balance equation is:

$6.21\frac{kJ}{K}*(75-25)=-8.00g*\frac{mol}{152.0g}*H_{c}$

So, the enthalpy of combustion can be calculated:

$H_{c}=-5899.5\frac{kJ}{mol}$

I will be happy to solve any doubt you have.

4 0

3 years ago

Light of wavelength 510 nm is used to illuminate normally two glass plates 24.3 cm in length that touch at one end and are separ

bulgar [2K]

Answer:

$m = 180 \ bright \ fringes$

Explanation:

From the question we are told that

The wavelength is $\lambda = 510 \ nm = 510 *10^{-9} \ m$

The length of the of the plate is $l = 24.3 \ cm = 0.243 \ m$

The radius of the wire is $r= 0.023 \ mm = 2.3 *10^{-5} \ m$

Generally the diameter of the wire which is the distance between the glass plates is mathematically represented as

$d = 2 * r$

=> $d = 2 * 2.3 *10^{-5}$

=> $d = 4.6 *10^{-5} \ m$

Generally the condition for constructive interference is mathematically represented as

$2 *d = m \lambda$

=> $m = \frac{2d}{\lambda}$

=> $m = \frac{2 * (4.6* 10^{-5})}{ 510 *10^{-9} }$

=> $m = 180 \ bright \ fringes$

3 0

2 years ago

Which statements best describe the second stage of cellular respiration? Check all that apply.

tamaranim1 [39]

Answer:

The correct answer is The stages happens in the cytoplasm.

Explanation:

5 0

3 years ago

Read 2 more answers

You have a length of tubing that is closed at one end. You cut the tubing into two pieces of unequal length, giving you a tube o

umka21 [38]

Answer:

The funda mental frequency of the original tube is 182Hz.

Explanation:

See the attachment for the calculation steps.

In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.

For closed tubes

f = nv/4L (n = 1, 3, 5,...n)

f = nv/2L (n = 1, 2, 3,...n)

The details of calculation can be found below in the attachment.