Answer:
14.79 kgm/s
Explanation:
Data provided in the question
Let us assume the mass of baseball = m = 0.145 kg
The Initial velocity of pitched ball = = 47 m/s
Final velocity of batted ball in the opposite direction = = -55m/s
Based on the above information, the change in momentum is
= 14.79 kgm/s
Hence, the magnitude of the change in momentum of the ball is 14.79 kg m/s
Answer:
s=4.44 m
Explanation:
Given that
Coefficient of the kinetic friction ,μ = 0.13
Initial velocity ,u= 3.4 m/s
Final velocity of the box ,v= 0 m/s
The acceleration due to friction force
a= - μ g
Now by putting the values in the above equation
a= - 0.13 x 10 ( take g= 10 m/s²)
a= - 1.3 m/s²
We know that
v²= u ² + 2 a s
s=distance
a=acceleration
v=final speed
u=initial speed
Now by putting the values in the above equation
0²= 3.4² - 2 x 1.3 x s
s=4.44 m
The distance cover by box will be 4.44 m.
