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nikdorinn [45]
3 years ago
9

An observer notes that the pitch of a sound is becoming progressively higher.the observer can conclude that the sound is moving

Physics
1 answer:
Dahasolnce [82]3 years ago
6 0
The observer can conclude that the sound is moving away from them and that its speed is increasing.
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How to solve 30(a)<br><br> Give solution asap.
expeople1 [14]

Answer:

They will not meet

h-hX=1.2*g*t²

hX=v0*t-(1/2*g*t²)

Explanation:

fall h=1/2*g*t²

elevation time if v0=20 m/s  te=v0/g=20 m/s /9.81 m/s²=2.0387s

hmax=v0²/(2*g)=(400 m²/s²)/19.62 m/s²2=20.387 m

free fall

t=2.0387s yields hX=1/2*g*t²=20.387 m

h-hX=200m - 20.387 m=179,613 m.

so, the second body has not enough initianoal speed to reach a meeting point

5 0
3 years ago
Which type of star is the sun
ahrayia [7]

G2V

The sun is a G2v type of star, a yellow dwarf and main sequence star.

3 0
3 years ago
Why does Alpha Centauri appear to be yellow-white?
viktelen [127]
Actually, the real reason it appears yellow-white is because of the temperature of the star. the stars that are hotter tend to be more blue and the stars that aren’t as hot tend to be more red/orange/yellow.
3 0
3 years ago
Read 2 more answers
I don’t know where each one goes
Usimov [2.4K]
I classified them by numbers 1 to 8
Force: #s 2,4,5,67
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3 0
2 years ago
Two balls of unequal mass are hung from two springs that are not identical. The springs stretch the same distance as the two sys
IRISSAK [1]

Answer:

b) Springs oscillate with the same frequency,

Explanation:

expression for frequency of vibration of mass hanging from a spring is given as follows

f = \frac{1}{2\pi} \times \sqrt{\frac{k}{m} }

k is force constant of spring and m is mass vibrating .

In the present case, if mass stretches the spring by x and remains balanced

mg = k x

\frac{k}{m} =\frac{g}{x}

g and x are same  for both cases

\frac{k}{m} will also be same for both cases .

Hence frequency of vibration will also be same for both the balls .

4 0
2 years ago
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