Answer:
t = 1.58 s
Explanation:
given,
Speed of ranger, v = 56 km/h
v = 56 x 0.278 = 15.57 m/s
distance, d = 65 m
deceleration,a = 3 m/s²
reaction time = ?
using stopping distance formula
t is the reaction time
t = 1.58 s
hence, the reaction time of the ranger is equal to 1.58 s.
Answer:
2.84 seconds
Explanation:
t = ?
distance = 125
Velocity origianal = 60 m/hr = 88 ft/s
AVERAGE velocity = 88/2 = 44 ft/s
44 t = 125
t = 125/44 = 2.84 s
Answer:
-5m/s
Explanation:
Since
acceleration=final velocity-initial velocity/time
2.5m/s^2=20m/s- initial velocity/10s
2.5m/s^2×10s= 20m/s -initial velocity
25m/s=20m/s - initial velocity
Initial velocity=20m/s-25m/s
= -5m/s