Answer:
81.04°C
Explanation:
Heat loss by water = Heat gained by Aluminum
Heat loss by water;
H = MCΔT
ΔT = 100 - T2
M = 580g
c = 4.2
H = 580 * 4.2 (100 - T2)
H = 243600 - 2436T2
Heat ganed by Aluminium
H = MCΔT
ΔT = T2 - 24
M = 900g
c = 0.9
H = 900 * 0.9 (T2 - 24)
H = 810 T2 - 19440
243600 - 2436T2 = 810 T2 - 19440
243600 + 19440 = 810 T2 + 2436T2
263040 = 3246 T2
T2 = 81.04°C
Assumption;
Assume that energy diffuses throughout the pan and water so that all parts reach the same final temperature.
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Equate the gravitational force to the electrostatic force:
<span>KC²/D² = Gm²/D² → C = m√[G/K] = 7.6√[6.67E-11/9E9] = 6.54E-10 coulombs </span>
<span>Number of electrons N = 6.24E18*C = 4.083E9 electrons</span>
Answer:
109.34 g
Explanation:
2NaOH(aq) + H2SO4(aq) ------> Na2SO4(aq) + 2H2O(l)
Number of moles of NaOH = 105g/40g/mol = 2.6 moles
From the reaction equation;
2 moles of NaOH yields 1 mole of sodium sulphate
2.6 moles of NaOH yields = 2.6 × 1/2 = 1.3 moles of sodium sulphate
Number of moles of H2SO4= 75.5g/98 g/mol = 0.77 moles
From the reaction equation;
1 mole of H2SO4 yields 1 mole of sodium sulphate
Hence, 0.77 moles of H2SO4 yields 0.77 moles of sodium sulphate
So H2SO4 is the limiting reactant.
Theoretical yield = number of moles × molar mass
= 0.77 mol ×142 g/mol
= 109.34 g
Answer:
The correct answer is 0, 235 mol
Explanation:
We use the formula PV =nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol:
1 atm x 5, 25l = n x 0, 082 l atm / K mol x 273 K
n= 1 atm x 5, 25l /0, 082 l atm / K mol x 273 K
n= 0, 235 mol
Answer:
One pattern could be a bear goes into hibernation once every year in the winter.
Explanation:
(Time of the year)
