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My name is Ann [436]
3 years ago
6

Pentane, C5H12, will react as shown below:

Chemistry
1 answer:
aivan3 [116]3 years ago
8 0
1) That looks right

2) Step 1: Moles=Mass/Mr, so it's 144/72= 2mol
    Step 2: Stoichiometry means the ratio of oxygen to pentane is 1:8 so moles of       oxygen is moles of pentane times 8. 2*8=16mol of oxygen
    Step 3: 16= 9.6*10^24

3) The ratio of oxygen to carbon in CO2 is 1:2
    so it's 192/3 = 64
    64*2=128g
Moles = Mass/Mr = 128/32 = 4mol = 2.41*10^24 atoms of oxygen
Basically you needed to work out the mass of oxygen using ratios before using a moles equation instead of just working with moles

4) True

5) <span>1C5H12+ 8O2----- 5CO2+ 6 H2O
</span>      32g        32g

Moles of oxygen = Mass/Mr = 32/32= 1mol so you'd need 0.125mol of pentane to react fully
Moles of pentane= Mass/Mr = 32/72=0.4mol so you'd need 3.2mol of oxygen to react fully

This makes oxygen the limiting factor, because you need more of it to react fully with the pentane, so we use oxygen 

Stoichiometry means for every 8mol of oxygen there's 5mol of CO2
So, 1/8*5=0.635mol of CO2
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Liquid nitrogen has a density of 0.808 g/mL and boils at 77 K. Researchers often purchase liquid nitrogen in insulated 195-L tan
Reika [66]

Answer:

The nswer to the question is

The maximum fraction of the air in the room that could be displaced by the gaseous nitrogen is 0.548 or 54.8 %

Explanation:

To solve the question we note that

The density of the liquid nitrogen = 0.808g/mL and the volume is 195 L tank (vaporised)

Therefore since density = mass/volume we have

mass = Density × volume = 0.808 g/mL × 195 L × 1000 ml/L =157560 g

In gaseous form the liquid nitrogen density =1.15 g/L

That is density = mass/volume and volume = mass/density = 157560 g/(1.15g/L)  or

volume = 137008.69565 L

The dimension of the room = 10 m × 10 m × 2.5 m = 250 m³ and

1 m³ is equivalent to 1000 L, therefore 250 m³ = 250 m³  × 1000 L/m³ = 250000L

Therefore fraction of the volume occupied by the gaseous nitrogen =

137008.69565 L/250000 L = 0.548

Therefore the gaseous nitrogen occpies 54.8% of the room

7 0
3 years ago
At 25 °c and 785 torr, carbon dioxide has a solubility of 0.0351 m in water. what is its solubility at 25 °c and 1510 torr?
jonny [76]
<span>When storing parts outside, it is best to keep them under tarps or wrapped to stay in compliance?

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4 0
3 years ago
Help :) For 100 points
Iteru [2.4K]

Answer:

6. Color Change.

Production of an odor.

Change of Temperature.

Explanation:

That is the only one I know :)

4 0
3 years ago
Read 2 more answers
ASAP , 8.81 g Carbon
xz_007 [3.2K]

The empirical formula : C₂Cl₇

The molecular formula : C₁₀Cl₃₅

<h3>Further explanation</h3>

Given

8.81 g Carbon

91.2 g Chlorine

Molar Mass: 1362.5 g/mol

Required

The empirical formula and molecular formula

Solution

Mol ratio :

C = 8.81 g : 12.011 g/mol =0.733

Cl = 91.2 g : 35,453 g/mol = 2..572

Divide by 0.733

C : Cl = 1 : 3.5 = 2 : 7

The empirical formula : C₂Cl₇

(The empirical formula)n = the molecular formula

(C₂Cl₇)n = 1362.5

(2x12.011+7x35.453)n=1362.5

(272.193)n=1362.5

n = 5

6 0
3 years ago
A graduated cylinder is filled 25.0 mL with water and a piece of granite is placed in the cylinder, displacing the level to 37.2
kvv77 [185]

The volume  of the granite piece  in Cm³  is 12.2 cm³

 <u><em>calculation</em></u>

volume of granite = (volume of cylinder after placing granite - volume  of  cylinder  before  placing  granite

 = 37.2 ml - 25.0 ml = 12.2 ml


convert ml  to Cm³

that is 1 ml = 1 cm³

       12.2 ml =  ? cm³

<em>by cross  multiplication</em>

=(12.2 ml x 1 cm³) / 1 ml = 12.2 cm³


3 0
3 years ago
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