3 years ago

What is the midpoint of line segment AB

1 answer:

3 0

I believe that it is E since it is pretty obvious where the middle is you just do rise/run which gives you 2,-1

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bazaltina [42]

Answer:

Step-by-step explanation:

DE given is

y''+8y'+15y=0, y(0)=0, y'(0)=1

Take Laplace on the DE

We get

$s^2 Y(s) -sY(0) -y'(0)+8(sY(s)-y(0))+15Y(s) =0\\s^2 Y(s) -s(0) -1+8(sY(s)-0)+15Y(s) =0\\Y(s)(s^2+8s+15)-1=0\\Y(s) = \frac{1}{s^2+8s+15}$

Simplify to get

Y(s) = $\frac{1}{2}[ {\frac{1}{s+3} -\frac{1}{s+5} }]$

Take inverse

$y(t) = \frac{e^{-3t} -e^{-5t}}{2}$

8 0

3 years ago

ch4aika [34]

360=24%0f x
360=24/100*x
360*100=24x
36000/24=x
therefore, x=1500......

4 0

3 years ago

Viefleur [7K]

X1 + x2 / 2 , y1 + y2 / 2

8 + x2 /2 = 6

So x is 4

9 + y2 /2 = 6

So y is 3.

Answer is B ( 4, 3)

Please Mark Brainliest if it helped

4 0

3 years ago

a_sh-v [17]

It is 16 I’ve done this question before

8 0

3 years ago

ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

you can see that the graph only extends from 2 to 5, and because of the closed circles you know its ≤ not < for the signs

8 0

3 years ago