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ludmilkaskok [199]
3 years ago
9

A piston in a heat engine does 500 joules of work, and 1,400 joules of heat are added to the system. Determine the change in int

ernal energy and explain how this example demonstrates the conservation of energy.
Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
8 0
The change is that the piston gets hotter? (Theres more heat in it)
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Hydrogen peroxide decomposes in presence of manganese (iv) oxide to give oxygen gas i). Draw a labelled diagram to show the volu
Effectus [21]

Answer:

Oxygen can be made from hydrogen peroxide, which decomposes slowly to form water and oxygen:

hydrogen peroxide → water + oxygen

2H2O2(aq) → 2H2O(l) + O2(g)

The rate of reaction can be increased using a catalyst, manganese(IV) oxide. When manganese(IV) oxide is added to hydrogen peroxide, bubbles of oxygen are given off.

Apparatus arranged to measure the volume of gas in a reaction. Reaction mixture is in a flask and gas travels out through a pipe in the top and down into a trough of water. It then bubbles up through a beehive shelf into an upturned glass jar filled with water. The gas collects at the top of the jar, forcing water out into the trough below.

To make oxygen in the laboratory, hydrogen peroxide is poured into a conical flask containing some manganese(IV) oxide. The gas produced is collected in an upside-down gas jar filled with water. As the oxygen collects in the top of the gas jar, it pushes the water out.

Instead of the gas jar and water bath, a gas syringe could be used to collect the oxygen

6 0
2 years ago
If a chemist has 17.8 moles of N2H4O3, what is the mass of the sample?<br><br> show work plz
harkovskaia [24]

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2 years ago
Can someone please help me with this question? I don't understand it
mr Goodwill [35]
There  are 3 different elements
8 0
3 years ago
Read 2 more answers
A chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution? A
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this is a dilution equation where 50.0 mL of 1.50 M H₂SO₄ is taken and added to 200 mL of water.

c1v1 = c2v2

where c1 is concentration and v1 is volume of the concentrated solution

and c2 is concentration and v2 is volume of the diluted solution to be prepared

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substituting these values in the formula

1.50 M x 50.0 mL = C x 250 mL

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concentration of the final solution is A) 0.300 M

4 0
3 years ago
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Pachacha [2.7K]

Answer:

I THINK NH3

Explanation:

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