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andriy [413]
3 years ago
6

How much energy is required to vaporize 2 kg of gold? Use the table below

Chemistry
1 answer:
Studentka2010 [4]3 years ago
8 0

Answer:

48

Explanation:

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The process that changes a substance from a liquid to a gas below the substance's boiling point
disa [49]
The answer is evaporation
3 0
4 years ago
What does ethylene glycol do to the solution in a vehicle’s radiator? It raises the boiling point and lowers the freezing point.
zheka24 [161]

Answer:

It raises the boiling point and lowers the freezing point.

Explanation:

It is used as antifreeze in the cooling circuits of internal combustion engines, that is, it is used to reduce the melting point of the solution.

By adding ethylene glycol I'm not only bringing the melting point to -13°C, but the boiling point of ethylene glycol is 197°C.

since these substances not only lower the freezing point but also increase the boiling point, they are also called a colligative agent

5 0
3 years ago
Read 2 more answers
What is the ground state electron configuration for magnesium?
Stella [2.4K]
Magnesium :

<span>[Ne] 3s²</span>

Answer A

hope this helps!

5 0
3 years ago
The volume of a sample of gas measured at 27 °C is 10.0 dm . What is the temperature when the volume is reduced to 9.0 dm at the
Mars2501 [29]

Answer:

T_2=24.3^{\circ} C

Explanation:

Given that,

The volume of a sample of gas measured at 27 °C is 10.0 dm.

We need to find the temperature when the volume is reduced to 9.0 dm at the same pressure.

According Charles law,

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Where, T₂ is new temperature

T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{9\times 27}{10}\\\\T_2=24.3^{\circ} C

So, the new temperature is 24.3^{\circ} C.

5 0
3 years ago
A chemist adds of a zinc nitrate solution to a reaction flask. Calculate the mass in kilograms of zinc nitrate the chemist has a
Ray Of Light [21]

Answer:

5.3 × 10⁻³ kg

Explanation:

There is some info missing. I think this is the original question.

<em>A chemist adds 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution to a reaction flask. Calculate the mass in kilograms of zinc nitrate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>

<em />

We have 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution. The moles of zinc nitrate are:

0.1350 L × 0.21 mol/L = 2.8 × 10⁻² mol

The molar mass of zinc nitrate is 189.36 g/mol. The mass corresponding to 2.8 × 10⁻² moles is:

2.8 × 10⁻² mol × 189.36 g/mol = 5.3 g

1 kilogram is equal to 1000 grams. Then,

5.3 g × (1 kg/1000 g) = 5.3 × 10⁻³ kg

8 0
3 years ago
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