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3 years ago

In the reaction Mg(s) + Br2() → MgBrz(s), what should be the coefficient for

Chemistry

1 answer:

lbvjy [14]3 years ago

6 0

Answer:

Explanation:

Chemical equation:

Mg + Br₂ → MgBr₂

Balanced chemical equation:

Mg + Br₂ → MgBr₂

Left hand side Right hand side

Mg = 1 Mg = 1

Br = 2 Br = 2

There are one Mg and 2 Br atoms on both side of equation thus this equation is balanced. Thus coefficient with bromine is 1.

Mg is present in group 2 it loses two valance electrons and get +2 oxidation state. Bromine is present in group 17 have 7 valence electrons. Thus one bromine atom need only one electron to complete the octet that's why two bromine atoms will attached with one magnesium atom to cancel the charge +2 and make the compound neutral.

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The expression of the theoretical yield (TY) in function of limiting reagent (LR) of a reaction is as follows: TY = ideal mole r

spin [16.1K]

Answer: The theoretical yield of acetanilide is 6.5 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For aniline:

Given mass of aniline = $4.50\times 10^0=4.50g$ (We know that: $10^0=1$ )

Molar mass of aniline = 93.13 g/mol

Putting values in equation 1, we get:

$\text{Moles of aniline}=\frac{4.50g}{93.13g/mol}=0.048mol$

For acetic anhydride:

To calculate the mass of acetic anhydride, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Volume of acetic anhydride = $(1.25\times \text{Mass of aniline})=1.25\times 4.50=5.625mL$

Density of acetic anhydride = 1.08 g/mL

Putting values in above equation:

$1.08g/mL=\frac{\text{Mass of acetic anhydride}}{5.625mL}\\\\\text{Mass of acetic anhydride}=(1.08g/mL\times 5.625mL)=6.08g$

Given mass of acetic anhydride = 6.08 g

Molar mass of acetic anhydride = 102.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of acetic anhydride}=\frac{6.08g}{102.1g/mol}=0.06mol$

The chemical equation for the reaction of aniline and acetic anhydride follows:

$C_6H_5NH_2+CH_3COOCOCH_3\rightarrow C_6H_5NHCOCH_3+CH_3COOH$

By Stoichiometry of the reaction:

1 mole of aniline reacts with 1 mole of acetic anhydride

So, 0.048 moles of aniline will react with = $\frac{1}{1}\times 0.048=0.048mol$ of acetic anhydride

As, given amount of acetic anhydride is more than the required amount. So, it is considered as an excess reagent.

Thus, aniline is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of aniline produces 1 mole of acetanilide

So, 0.048 moles of aniline will produce = $\frac{1}{1}\times 0.048=0.048mol$ of acetanilide

Now, calculating the theoretical yield of acetanilide by using equation 1:

Moles of acetanilide = 0.048 moles

Molar mass of acetanilide = 135.17 g/mol

Putting values in equation 1, we get:

$0.048mol=\frac{\text{Mass of acetanilide}}{135.17g/mol}\\\\\text{Mass of acetanilide}=(0.048mol\times 135.17g/mol)=6.5g$

Hence, the theoretical yield of acetanilide is 6.5 grams.

3 0

4 years ago

What is the acknowledgment to ''Do all liquids evaporate at the same rate?'

natita [175]

'Do all liquids evaporate at the same rate
that would be false

4 0

3 years ago

How can a chemical reaction be sped up?Select from the drop-down menu to correctly complete the statement.

lara31 [8.8K]

Answer: Catalyst

Explanation: it speeds it up lol but basically the catalyst helps speed up the chemical reaction by reducing the activation energy or changing the reaction machenism/

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3 years ago

What is the correct name of this compound?

Reika [66]

Answer:

7. 3–ethyl–6 –methyldecane

8. 5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

Explanation:

It is important to note that when naming organic compounds having two or more different substituent groups, we simply name them alphabetically.

The name of the compound given in the question above can be written as follow:

7. Obtaining the name of the compound.

Compound contains:

I. Decane.

II. 3–ethyl.

III. 6 –methyl.

Naming alphabetically, we have

3–ethyl–6 –methyldecane

8. Obtaining the name of the compound.

Compound contains:

I. 2,2–dimethyl.

II. 4–propyl.

III. 4 –heptene.

IV. 5–ethyl.

Naming alphabetically, we have

5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

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3 years ago

what information can a foliated metamorphic rock provide you about the conditions under which it formed

uysha [10]

The information that a foliated metamorphic rock provide about the conditions it was formed under are:(for many diffrent rocks like Phyllite and Amphibolite)
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