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Kaylis [27]
3 years ago
15

When cleaning up a local beach, students found many different particles that were in the water that affected the shoreline, like

litter and gasoline. Which of the following describe how these items would need to separated from the water? Why? Question 5 options: Litter would need to be physically separated with water and gasoline would need to be chemically separated from water, because both form a mixture with the water. Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water. Both gasoline and litter would need to be chemically separated from the water, because both form new bonds with the water. Both gasoline and litter would need to be chemically separated from the water, because neither bonds with the water.
Physics
2 answers:
Nonamiya [84]3 years ago
8 0
C both gasoline and litter should be physically seperated
shusha [124]3 years ago
6 0

D. Both gasoline and litter would need to be Physically separated from the water, because neither bonds with the water.

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Why do you think Saturn and Jupiter have more moons than the other planets<br> in our solar system?
Aneli [31]

Answer:

yeah

Explanation:

6 0
3 years ago
Which therapies are associated with ultrasound? Check all that apply.
goldenfox [79]

Answer:

Need a picture

-Malignant tissue

-Over the lower abdomen

-during pregnancy

-Over an infection

Explanation:

IDK if this helps bc there is no picture, but here ya go

3 0
4 years ago
Diagnostic ultrasound of frequency 3.82 MHz is used to examine tumors in soft tissue. (a) What is the wavelength in air of such
maxonik [38]

Explanation:

It is given that,

Frequency of diagnostic ultrasound, f = 3.82 MHz = 3820 Hz

The speed of the sound in air, v = 343 m/s

(a) We need to find the wavelength in air of such a sound wave. Let it is given by λ₁

i.e. \lambda=\dfrac{v}{\nu}

\lambda_1=\dfrac{343\ m/s}{3820\ Hz}

\lambda_1=0.089\ m

(b) If the speed of sound in tissue is 1650 m/s .

\lambda_2=\dfrac{v}{\nu}

\lambda_2=\dfrac{1650\ m/s}{3820\ Hz}

\lambda_2=0.43\ m

Hence, this is the required solution.

7 0
3 years ago
According to newtons third law of motion action nd reaction forces are equal in magnitudes nd opposite in direction but they do
snow_lady [41]

Because the action and the reaction forces act on different objects

Explanation:

Newton's third law of motion states that:

<em>"When an object A exerts a force on an object B (action), then object B exerts an equal and opposite force (reaction) on object A"</em>

From the statement above, we clearly see that the two forces mentioned in the law act on different objects. In fact, the action is exerted on object B, while the reaction is exerted on object A.

When we are considering the free-body diagram of an object, we just represent all the forces acting on that object, but not the forces exerted on other objects: this means that the action and the reaction never appear in the same free-body diagram of the same object, so they do not cancel out, simply because they are applied to different objects.

Learn more about Newton's third law:

brainly.com/question/11411375

#LearnwithBrainly

6 0
3 years ago
Does the elf owl's small size allow it to live in cacti
kaheart [24]
Habitat
-In the Sonoran Desert region, elf owls are found mainly in riparian habitats (places where there is water), or in areas where saguaro cactus are plentiful.

Range
-Elf Owls are found from the southwest USA to Central Mexico and Baja California. Northern populations winter in Central Mexico and on the Pacific slope north to Sinaloa, Mexico.

Wild Status
-The most important threat to the elf owl is habitat loss both of its riparian forest habitat and desert-scrub habitats. In Arizona, the elf owl is not uncommon, but it's numbers are decreasing in California and Texas.

-So I mean like ya it's possible that they could live in cacti. Sorry that I couldn't give you a straight answer.



couldlive in
3 0
3 years ago
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