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Kaylis [27]
2 years ago
15

When cleaning up a local beach, students found many different particles that were in the water that affected the shoreline, like

litter and gasoline. Which of the following describe how these items would need to separated from the water? Why? Question 5 options: Litter would need to be physically separated with water and gasoline would need to be chemically separated from water, because both form a mixture with the water. Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water. Both gasoline and litter would need to be chemically separated from the water, because both form new bonds with the water. Both gasoline and litter would need to be chemically separated from the water, because neither bonds with the water.
Physics
2 answers:
Nonamiya [84]2 years ago
8 0
C both gasoline and litter should be physically seperated
shusha [124]2 years ago
6 0

D. Both gasoline and litter would need to be Physically separated from the water, because neither bonds with the water.

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What is the magnitude of the resultant of a 7.0-N force acting vertically upward and a 5.0-N force acting horizontally.
irakobra [83]

Answer:

Resultant force = 8.6N

Explanation:

Using Pythogorus' theorem

{a}^{2}  +  {b}^{2}  =  {c }^{2}  \\  {7}^{2}  +  {5}^{2}  =  {r}^{2} \\ 49 + 25 =  {r}^{2}  \\ 74 =  {r}^{2}  \\   \sqrt{74}  =   \sqrt{ {r }^{2} }  \\ 8.6 = r \\

Resultant force = 8.6N

6 0
2 years ago
BRAINLIEST FOR THE FIRST TO ANSWER
Sonja [21]

Answer:

Wrong its B Use a different amount of mass in the cart for five different trials, roll the cart down a ramp with the same slope for each trial, and measure how long it takes the cart to roll one meter each time.

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8 0
3 years ago
A cheetah can run at a maximum speed 103 km/h and a gazelle can run at a maximum speed of 76.5 km/h. If both animals are running
Katena32 [7]

Answer:

1

 t_a  =  13.49 \  s

2

 The distance is   D = 55.2 \  m    

Explanation:

From the question we are told that

   The maximum speed of the cheetah is  v =  103 \  km/h =  28.61 \  m/s

    The maximum of  gazelle is  u =  76.5 \  km/h =  21.25 \  m/s

     The distance ahead is d =  99.3 \  m

Let  t_a denote the time which the cheetah catches the gazelle

Gnerally the equation representing the distance the cheetah needs to move in order to catch the gazelle is

           v* t_a = d +  u* t_a

=>          28.61 t_a = 99.3 +  21.25t_a

=>          7.36 t_a = 99.3

=>         t_a  =  13.49 \  s

Now at t =  7.5 s  

             7.5 v = D+  7.5u

=>          28.61 * 7.5  = D +  21.25* 7.5

=>          7.36 *  7.5 =D

=>         D = 55.2 \  m        

Hence the for the gazelle to escape the cheetah it must be 55.2 m

5 0
3 years ago
What effort force will be required to lift the 20 N object using the pulley above?
Umnica [9.8K]

Answer:

I think it is 5N.

Explanation:

4 0
3 years ago
Which equation is used to determine the density of a substance?
Mademuasel [1]
The answer is D=M/V hope it helps!!
3 0
3 years ago
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