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4 years ago

These are two angles that add up to 180° that share a common vertex.

Physics

2 answers:

Andre45 [30]4 years ago

5 0

Answer:

Adjacent supplementary angles

Explanation:

Two angles are supplementary when they add up to 180⁰. Two angles are adjacent supplementary angles if:

they have a common side
they have a common vertex
they don't overlap

trasher [3.6K]4 years ago

4 0

Answer:

Explanation:

This are adjacent supplementary angles

The sum of two adjacent supplementary angles gives 180°.

Two angles that add up to 180° that share a common vertex are ADJACENT SUPPLEMENTARY ANGLES.

Check attachment for a clearer view. I

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Light of a given wavelength is used to illuminate the surface of a metal, however, no photoelectrons are emitted. in order to ca

solniwko [45]

We will decrease the wavelength of light in order to cause electrons to be ejected from the surface of this metal.

We have a Light of a given wavelength that is used to illuminate the surface of a metal, however, no photoelectrons are emitted.

We have to find out what can we do in order to cause electrons to be ejected from the surface of this metal.

<h3>What is Photoelectric Effect ?</h3>

The emission of electrons from the surface of the metal when the light of specific frequency (greater than the threshold frequency) falls over it is called photoelectric effect.

Light consists of photons. The energy associated with the photons is used to emit out the electrons from the surface of metal. We know that - Energy can neither be created nor be destroyed and it can only be transferred from one body to another. Hence, the energy of these moving photons is used to emit electrons from the metal surface. The energy associated with the photon is given by -

E = hμ

Where - μ is the frequency of light an h is Planck's constant.

Now, we can see that the energy of the photon is directly proportional to the frequency of light. The minimum frequency required to eject the electron from the metal surface is called Threshold frequency. Thus, we can emit the electron from the metal surface by using the light of frequency greater than threshold frequency.

Hence, we will increase the frequency of light in order to cause electrons to be ejected from the surface of this metal

To solve more questions on Photoelectric Effect, visit the link below -

brainly.com/question/9260704

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8 0

2 years ago

Quantitative data is _____________ Lesson 1.11

alex41 [277]

Answer:

gathered by using measurement tools and math

Explanation:

Quantitative data is often gathered by using measurement tools and math.

A quantitative data set is assigned values and numbers in order to solve a problem or for the purpose of a study.

Each data set has a unique numerical value and can be counted.
Qualitative data set does not use numerals and numbers.
It engages the senses to make some scientific deductions.
Examples are measurement of volume, distance, length, time, number of moles e.t.c
Qualitative data sets include taste, smell, color e.t.c

5 0

3 years ago

A 2 kg melon is balanced on your bald uncle’s head. His son, Throckmorton, shoots a 50 g (0.05kg) arrow at it with a speed of 30

sineoko [7]

Answer:

The speed of the melon as it flies off the man’s head is 0.3 m/s.

Explanation:

Given;

mass of the melon, m₁ = 2 kg

initial speed of the melon, u₁ = 0

mass of arrow, m₂ = 0.05 kg

initial speed of the arrow, u₂ = 30 m/s

final speed of the arrow, v₂ = 18 m/s

let v₁ be the final speed of the melon as it flies off the man's head.

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

2(0) + 0.05 x 30 = 2v₁ + 0.05 x 18

1.5 = 2v₁ + 0.9

2v₁ = 1.5 - 0.9

2v₁ = 0.6

v₁ = 0.6 / 2

v₁ = 0.3 m/s

Therefore, the speed of the melon as it flies off the man’s head is 0.3 m/s.

4 0

3 years ago

A car of mass 1600 kg traveling at 27.0 m/s is at the foot of a hill that rises vertically 135 m after travelling a distance of

Zarrin [17]

Answer:

Neglecting any frictional losses, the average power delivered by the car's engine is 10565 W

Explanation:

The energy conservation law indicates that the energy must be the same at the bottom of the hill and at the top of the hill.

The energy at the bottom is only the Kinect energy (K_1) of the car in motion, but in the top, the energy is the sum of its Kinect energy (K_2), potential energy (P) and the work (W) done by the engine.

$K_1 = K_2 + P + W$

then, the work done by the engine is:

$W = K_1 - K_2 - P$

The formulas for the Kinetic and potential energy are:

$K=\frac{1}{2}mV^2\\P=mgh$

where, m is the mass of the car, V the velocity, g the gravity and h is the elevation of the hill.

Using the formulas:

$W=\frac{1}{2}mV_1^2-\frac{1}{2}mV_2^2-mgh$

Replacing the values:

$W=\frac{1}{2}(1600Kg)(27m/s)^2-\frac{1}{2}(1600Kg)(14m/s)^2-(1600Kg)(9.8m/s^2)(135m)\\W=-1690400 J$

The negative of this value indicates the direction of the work done, but for the problem, you only care about the magnitude, so the power is W=1690400 J. Now, the power is equal to work/time so you need to find the time the car took to get to the top of the hill.

The average speed of the car is (27+14)/2=20m/s, and t=d/v so the time is:

$t=\frac{3200m}{20m/s}=160s$