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VLD [36.1K]
3 years ago
14

What is most responsible for changing the boiling and freezing points of a solvent?

Chemistry
2 answers:
Alinara [238K]3 years ago
5 0
The most responsible values for a change to happen on the boiling and freezing point of a solvent is the number of solute particles.This is generally known as colligative properties. By simply adding a solute, regardless of its identity, it can change the properties of the solvent. Colligative properties includes, vapor pressure lowering, boiling point elevation, freezing point depression, and osmostic pressure.
NemiM [27]3 years ago
3 0
The most responsible for changing the boiling and freezing points of a solvent is the number of the solute particles.
Colligative properties-involves simple adding a solute changes the properties of the solvent, this is why salt is added to the roads in winter time to prevent water from freezing. Freezing point is the temperature at which a liquid becomes a solid, it is normally lower than the melting point in the cases of mixtures and for certain organic compounds such as fats.
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The specific rate constant, k, for radioactive beryllium–11 is 0.049 s–1. What mass of a 0.500 mg sample of beryllium–11 remains
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<u>Answer: </u>The mass of sample that remained is 0.127 mg

<u>Explanation:</u>

The integrated rate law equation for first-order kinetics:

k=\frac{2.303}{t}\log \frac{a}{a-x} ......(1)

Given values:

a = initial concentration of reactant = 0.500 mg

a - x = concentration of reactant left after time 't' = ?mg

t = time period = 28 s

k = rate constant = 0.049s^{-1}

Putting values in equation 1:

0.049s^{-1}=\frac{2.303}{28s}\log (\frac{0.500}{(a-x)})\\\\\log (\frac{0.500}{(a-x)})=\frac{0.049\times 28}{2.303}\\\\\frac{0.500}{a-x}=10^{0.5957}\\\\frac{0.500}{a-x}=3.94\\\\a-x=\frac{0.500}{3.942}=0.127mg

Hence, the mass of sample that remained is 0.127 mg

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