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3 years ago

9

Explain the difference in the reducing abilities for NaBH4 and LiBH4 in ether.

1 answer:

oee [108]3 years ago

6 0

Answer:

NaBH4 is less reactive than LiAlH4 but is otherwise similar. It is only powerful enough to reduce aldehydes, ketones and acid chlorides to alcohols: esters, amides, acids and nitriles are largely untouched. It can also behave as a nucleophile toward halides and epoxides.

Explanation:

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4 years ago

Metals and their ore

Maksim231197 [3]

Answer:

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Explanation:

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3 years ago

The molar solubility of zns is 1.6 Ã 10-12 m in pure water. Calculate the ksp for zns.

Oksi-84 [34.3K]

Answer:

The solubility product of zinc sulfide is $2.56\times 10^{-24}$ .

Explanation:

Solubility of the zinc sulfide = $S=1.6\times 10^{-12}$

$ZnS\rightleftharpoons Zn^{2+}+S^{2-}$

S S

The expression of solubility product is given by :

$K_{sp}=[Zn^{2+}]\times [S^{2-}]$

$K_{sp}=S\times S=S^2$

$=1.6\times 10^{-12}\times 1.6\times 10^{-12}=2.56\times 10^{-24}$

The solubility product of zinc sulfide is $2.56\times 10^{-24}$ .

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