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4 years ago

Which granulated leukocyte is most likely to be active during a bacterial infection?

1 answer:

7 0

It seems that you have missed the necessary options for us to answer this question, so I had to look for it. Anyway, here is the answer. The granulated leukocyte that is most likely to be active during a bacterial infection is the NEUTROPHIL. Hope this answers your question.

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Which one is the answer?

nadya68 [22]

I would go with C because that seems like the best answer choice

3 0

3 years ago

Write a conclusion statement that addresses the following questions: • Explain what the color change indicated about the changes

Novay_Z [31]

Answer: try to understand coz the question is not valid

Explanation: Explain the relationship between forward and reverse reactions at equilibrium and predict how changing the amount of a reactant or product (creating a stress) will affect that relationship.For example (select one from each underlined section)If the amount of (reactant or product) increases, the rate of the (forward or reverse)reaction will (increase or decrease)to reach a new equilibrium. If the amount of (reactant or product) decreases, the rate of the (forward or reverse)reaction will (increase or decrease)to reach a new equilibrium. Procedure: Access the virtual lab and complete the inquiry experiment

5 0

3 years ago

What type of solution is formed when steam from boiling water evaporates into the air

Hoochie [10]

That specific kind is called gas.

When you put water in a freezing temprature it becomes solid.
When you boil water it becomes gas

7 0

3 years ago

Two liquids are analyzed and found to both be 85.7% carbon and 14.3% hydrogen. At 750 mmHg and 150 C, both are gases. At these c

vodomira [7]

Answer:

Molecular formula A: C₅H₁₀

Molecular formula B: C₇H₁₄

Explanation:

It is possible to obtain empirical formula of compounds using percent composition, thus:

C: 85.7% × (1mol / 12.01g) = 7.136 moles C

H: 14.3% × (1mol / 1.01g) = 14.158 moles H

Mole ratio of H:C is:

14.158mol / 7.136mol = 2

That means in compounds A and B you have 2 hydrogens per atom of carbon and empirical formila is:

CH₂

Using PV = nRT, moles of A and B are:

Where P is pressure (750mmHg / 760 = 0.987atm), V is volume (0.8000L), R is gas constant (0.082atmL/molK), and T is temperature (150°C +273.15 = 423.15K)

Moles A and B: n = PV / RT

n = 0.987atm×0.8000L / 0.082atmL/molK×423.15K

n = 0.0228 moles of A and B.

Using the mass of A and B it is possible to find molar mass of each compound:

A = 1.60g / 0.0228mol = 70.31g/mol

B = 2.22g / 0.0228mol = 97.56g/mol

As empirical formula of both compounds is CH₂, (molar mass = 14.03g/mol). Molecular formula of compounds is:

A = 70.31g/mol / 14.03g/mol = 5 → Molecular formula: 5×CH₂ = C₅H₁₀

B = 97.56g/mol / 14.03g/mol = 7 → Molecular formula: 7×CH₂ = C₇H₁₄

8 0

3 years ago

How do the atomic mass and atomic number compare for helium?

Sonja [21]

The atomic mass is greater than the atomic number.

4 0

3 years ago

Read 2 more answers