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yanalaym [24]
4 years ago
5

Which granulated leukocyte is most likely to be active during a bacterial infection?

Chemistry
1 answer:
77julia77 [94]4 years ago
7 0
It seems that you have missed the necessary options for us to answer this question, so I had to look for it. Anyway, here is the answer. The granulated leukocyte that <span> is most likely to be active during a bacterial infection is the NEUTROPHIL. Hope this answers your question.</span>
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Debido a que propiedad un cuerpo flota en el agua y otro no​
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Answer:

cuerpo flota o se hunde es su densidad con respecto a la del líquido en que se sumerge. En cambio, una nuez (densidad = 0.5) flotara en ambos líquidos mientras que una piedra (densidad = 2) se hundirá.

Explanation:

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3 years ago
Question 1 Multiple Choice Worth 2 points)<br> (03.05 LC)<br> Which statement is true?
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What begins to happen to radioactive uranium as soon as a mineral containing it crystallizes from magma?
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What do we call the study of matter and how matter changes?
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Answer:

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3 years ago
If an equal number of moles of reactants are used, do the following equilibrium mixtures contain primarily reactants or products
puteri [66]

<u>Answer:</u>

<u>For a:</u> The equilibrium mixture contains primarily reactants.

<u>For b:</u> The equilibrium mixture contains primarily products.

<u>Explanation:</u>

There are 3 conditions:

  • When K_{eq}>1; the reaction is product favored.
  • When K_{eq}; the reaction is reactant favored.
  • When K_{e}=1; the reaction is in equilibrium.

For the given chemical reactions:

  • <u>For a:</u>

The chemical equation follows:

HCN(aq.)+H_2O(l)\rightleftharpoons CN^-(aq.)+H_3O^+(aq.);K_{eq}=6.2\times 10^{-10}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[CN^-][H_3O^+]}{[HCN][H_2O]}=6.2\times 10^{-10}

As, K_{eq}, the reaction will be favored on the reactant side.

Hence, the equilibrium mixture contains primarily reactants.

  • <u>For b:</u>

The chemical equation follows:

H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g);K_{eq}=2.51\times 10^{4}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[HCl]^2}{[H_2][Cl_2]}=2.51\times 10^{4}

As, K_{eq}>1, the reaction will be favored on the product side.

Hence, the equilibrium mixture contains primarily products.

4 0
3 years ago
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