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BlackZzzverrR [31]

3 years ago

9

You are in the room with several objects, the temperature in the room is 21 celcius, what can you assume about the temperatures

of the objects in the room?

1 answer:

Brilliant_brown [7]3 years ago

4 0

Answer:the objects will be about the same temperature as the room

Explanation:

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Give the postional isomers of 2 halopropane<br>(CH3)2CH

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Give the positional isomers of 2 halopropane

(CH3)2CH

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What form of matter is made from only one type of atom? compound molecule material element

Lelechka [254]

<span>Elements are matter made of one kind of atom.</span>

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2 years ago

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Please help... I am begging...

iVinArrow [24]

Answer:

The number, such as 98.7 FM, of a radio station represents:

<u>the frequency in which is transmitted the radio signal</u>.

Explanation:

<em>The radio FM is the modulated frequency, which means that all the information is sent by just a signal, with different frequencies which difference them</em>, <u>the radio FM use the frequencies from 88 MHz until 108 Mhz (MHz is a measuring unit for the frequency), with a minimal space among them of 0.2 MHz</u>, this last means that you could find a signal in 88.0 MHz, and the next should be 88.2 MHz, next 88.4 MHz and so (at least, regularly the space between two frequencies is more than 0.2 MHz).

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3 years ago

Consider the following chemical reaction: 2KCl + 3O2 --> 2KClO3. If you are given 100.0 moles of KCl and 100.0 moles of O2...

g100num [7]

Answer:

O₂; KCl; 33.3

Explanation:

We are given the moles of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

2KCl + 3O₂ ⟶ 2KClO₃

n/mol: 100.0 100.0

1. Identify the limiting reactant

(a) Calculate the moles of KClO₃ that can be formed from each reactant

(i)From KCl

$\text{Moles of KClO}_{3} = \text{100.0 mol KCl} \times \dfrac{\text{2 mol KClO}_{3}}{\text{2 mol KCl}} = \text{100.0 mol KClO}_{3}$

(ii) From O₂

$\text{Moles of KClO}_{3} = \text{100.0 mol O}_{2} \times \dfrac{\text{2 mol KClO}_{3}}{\text{3 mol O}_{2}} = \text{66.67 mol KClO}_{3}$

O₂ is the limiting reactant, because it forms fewer moles of the KClO₃.

KClO₃ is the excess reactant.

2. Moles of KCl left over

(a) Moles of KCl used

$\text{Moles used} = \text{100.0 mol O}_{2} \times \dfrac{\text{2 mol KCl}}{\text{3 mol O}_{2}} = \text{66.67 mol KCl}$

(b) Moles of KCl left over

n = 100.0 mol - 66.67 mol = 33.3 mol

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3 years ago

What is a non-example of an electrical conductor?

goblinko [34]

Answer: Sulphur, Phosphorus, Wood are non-conductors of electricity due to no presence of free electrons in outermost shell.

Explanation:

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2 years ago

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