Answer:
A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.
Explanation:
Hello,
A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.
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Answer: 1.414x10^24 molecules in 94.4g MgO
Explanation: molar mass MgO 40.204
molecules in 40.204 g MgO = avogadro number
molecules in 94.4 g MgO = (94.4/40.204)*avogadro number
(94.4/40.204)*6.02214076*10^23 = 14.14x10^23
<h3>
Answer:</h3>
78.75 K
<h3>
Explanation:</h3>
<u>We are given;</u>
- Initial pressure, P₁ = 500 torr
- Initial temperature,T₁ = 225 K
- Initial volume, V₁ = 3.3 L
- Final volume, V₂ = 2.75 L
- Final pressure, P₂ = 210 torr
We are required to calculate the new temperature, T₂
- To find the new temperature, T₂ we are going to use the combined gas law;
- According to the combined gas law;
P₁V₁/T₁ = P₂V₂/T₂
We can calculate the new temperature, T₂;
Rearranging the formula;
T₂ =(P₂V₂T₁) ÷ (P₁V₁)
= (210 torr × 2.75 L × 225 K) ÷ (500 torr × 3.3 L)
= 78.75 K
Therefore, the new volume of the sample is 78.75 K
