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3 years ago

Write 4.5kg : 1500g as a ratio in its simplest form

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

6 0

Answer:

(4.5kg : 1500g) ÷ 4.5

=(4.5kg : 1.5kg) ÷ 4.5

=1kg : 0.33kg

Margaret [11]3 years ago

3 0

Answer:

3 : 1

Step-by-step explanation:

The values must be in the same quantity

1 Kg = 1000 g

4.5 Kg = 4.5 × 1000 = 4500 g

Then

4.5 Kg : 1500 g

= 4500 g : 1500 g ( divide both parts by 1500 )

= 3 : 1 ( in simplest form )

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Solve: -3/4x - 8 + 5/4x - 4 = 9 x=?

ExtremeBDS [4]

Answer: x=42

Step-by-step explanation: In the picture

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3 years ago

The volume V of a solid right circular cylinder is given by V = πr2h where r is the radius of the cylinder and h is its height.

emmainna [20.7K]

Answer:

8.20in³

Step-by-step explanation:

Given V = πr²h

r is the radius = 1.5in

h is the height = 6in

thickness of wall of the cylinder dr = 0.04in

top and bottom thickness dh 0.07in+0.07in = 0.14in

To compute the volume, we will find the value of dV

dV = dV/dr • dr + dV/dh • dh

dV/dr = 2πrh

dV/dh = πr²

dV = 2πrh dr + πr² dh

Substituting the values into the formula

dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14

dV = 2π (0.36)+π(1.89)

dV = 0.72π+1.89π

dV = 2.61π

dV = 2.61(3.14)

dV = 8.1954in³

Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)

7 0

3 years ago

At a basketball game, a vender sold a combined total of 100 sodas and hot dogs. The number of sodas sold was 38 more than the nu

Lina20 [59]

Answer:

64 sodas

36 hotdogs

Step-by-step explanation:

Well i just guessed and checked but thats the answer

6 0

3 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

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3 years ago

Need help with all three questions...

MA_775_DIABLO [31]

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3 years ago