Answer:
18.6012339739 A
Explanation:
= Vacuum permeability = 
L = Length of wire = 55 cm
N = Number of turns = 4000
I = Current
Magnetic field is given by
The current necessary to produce this field is 18.6012339739 A
Answer:
M_c = 100.8 Nm
Explanation:
Given:
F_a = 2.5 KN
Find:
Determine the moment of this force about C for the two cases shown.
Solution:
- Draw horizontal and vertical vectors at point A.
- Take moments about point C as follows:
M_c = F_a*( 42 / 150 ) *144
M_c = 2.5*( 42 / 150 ) *144
M_c = 100.8 Nm
- We see that the vertical component of force at point A passes through C.
Hence, its moment about C is zero.
The moment of inertia is the rotational analog of mass, and it is given by
the product of mass and the square of the distance from the axis.
- The moment of inertia changes as the position of the weight is changed, which indicates that; statement is incorrect
Reasons:
The weight on each arm that have adjustable positions can be considered as point masses.
The moment of inertia of a point mass is <em>I</em> = m·r²
Where;
m = The mass of the weight
r = The distance (position) from the center to which the weight is adjusted
Therefore;
The moment of inertia, <em>I </em>∝ r²
Which gives;
Doubling the distance from the center of rotation, increases the moment of inertia by factor of 4.
Therefore, the statement contradicts the relationship between the radius of rotation and moment of inertia.
Learn more about moment of inertia here:
brainly.com/question/4454769
Answer:
The minimum value of width for first minima is λ
The minimum value of width for 50 minima is 50λ
The minimum value of width for 1000 minima is 1000λ
Explanation:
Given that,
Wavelength = λ
For D to be small,
We need to calculate the minimum width
Using formula of minimum width
Where, D = width of slit
= wavelength
Put the value into the formula
Here, 
should be maximum.
So. maximum value of is 1
Put the value into the formula
(b). If the minimum number is 50
Then, the width is
(c). If the minimum number is 1000
Then, the width is
Hence, The minimum value of width for first minima is λ
The minimum value of width for 50 minima is 50λ
The minimum value of width for 1000 minima is 1000λ
Answer: Noise above 70 dB can cause hearing damage
Explanation:
