f(n) is the nth term
Each term f(n) is found by adding the terms just prior to the nth term. Those two terms added are f(n-1) and f(n-2)
The term just before nth term is f(n-1)
The term just before the (n-1)st term is f(n-2)
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For example, let's say n = 3 indicating the 3rd term
n-1 = 3-1 = 2
n-2 = 3-2 = 1
So f(n) = f(n-1) + f(n-2) turns into f(3) = f(2) + f(1). We find the third term by adding the two terms just before it.
f3) = third term
f(2) = second term
f(1) = first term
Answer:
7959.83
Step-by-step explanation:
A = P ( 1+r/n)^ nt
Where A is the amount in the account
P is the principal
r is the rate
n is the number of compoundings per year
t is the years
A =3000 ( 1+.10/2)^ 2*10
A =3000 ( 1+.05)^ 20
=7959.83
The y is greater than the function
Answer:3/2
3x3-2x2-7x+6=x+1(Multiply the numbers)
9-4-7x+6=x-1(Calculate)
11-7x=x-1(Move the terms)
-7x-x=-1-11(Collect like terms&calculate)
-8x=-12(Divide both sides by -8)
x=3/2
