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2 years ago

Why is electron capture accompanied by the emission of an X-ray?

Chemistry

1 answer:

marissa [1.9K]2 years ago

8 0

Answer:

During electron capture, an inner electron usually from K shell or L shell combines with proton of the nucleus thereby changing proton to neutron. The process of electron capture is also accompanied by the emission of neutrino. It generally occurs in proton rich nucleus. The capture of electron by the proton creates a hole in the electron shell. The hole created is generally filled by the dropping down of a higher level electron with the emission of X -ray.

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What is the molarity of 10g of carbon in a 500L solution?

Zolol [24]

Answer:

Molarity is the number of moles in a liter of a substance.

Molarity= Mole/volume

Mass= 10g

Molar mass of Carbon=12g

To calculate the mole we use the formula: mole= mass/molar mass

Mole = 10g/12g

Mole = 0.83

Molarity= 0.83/500 =0.0017moles per liter

5 0

3 years ago

A potassium atom (atomic number 19) and a bromine atom (atomic number 35) can form a chemical bond through a transfer of one ele

liubo4ka [24]

Answer:

A potassium atom (atomic number 19) and a bromine atom (atomic number 35) can form a chemical bond through a transfer of one electron. The potassium ion that forms has 18 electrons. What best describes the bromide ion that forms? It is a negative ion that has one more valence electron than a neutral bromine atom.

Explanation:

7 0

2 years ago

Name the two possible products in the precipitation reaction of copper (II) chloride and sodium phosphate. Use the charges on th

satela [25.4K]

Answer:

General equation for a double-displacement reaction:

AB + CD --> AC + BD

• sodium chloride – NaCl copper sulfate – CuSO₄

NaCl + CuSO₄ --> Na₂SO₄ + CuCl₂

The products formed are sodium sulfate and copper (II) chloride.

Copper (II) chloride forms a blue colored solution.

• sodium hydroxide – NaOH copper sulfate – CuSO₄

NaOH + CuSO₄ --> Na₂SO₄ + Cu(OH)₂

The products formed are sodium sulfate and copper (II) hydroxide.

Copper (II) hydroxide forms a blue colored solution.

• sodium phosphate – Na₂HPO₂ copper sulfate – CuSO₄

Na₂HPO₄ + CuSO₄ --> Na₂SO₄ + CuHPO₄

The products formed are sodium sulfate and copper (II) hydrogen phosphate.

Copper (II) hydrogen phosphate forms a blue colored solution.

• sodium chloride – NaCl silver nitrate – AgNO₃

NaCl + AgNO₃--> AgCl + NaNO₃

The products formed are silver chloride and sodium nitrate.

Silver chloride forms a white precipitate.

• sodium hydroxide – NaOH silver nitrate – AgNO₃

NaOH + AgNO₃ --> NaNO₃ + AgOH

The products formed are silver hydroxide and sodium nitrate.

Silver hydroxide forms a white precipitate.

• sodium phosphate – Na₂HPO₄ silver nitrate – AgNO₃

Na₂HPO₄ + AgNO₃ --> NaNO₃ + Ag₂HPO₄

The products formed are sodium nitrate and silver hydrogen phosphate.

Silver hydrogen phosphate forms a colorless solution.

Explanation:

5 0

3 years ago

Convert 3.2 ft^2 to square inches

tangare [24]

460.8 square inches

3.2 * 144 = 460.8

6 0

3 years ago

Select all the correct answers.

stich3 [128]

Answer : The products of the acid-base reaction between $HClO_3$ and LiOH are, $LiClO_3$ and $H_2O$

Explanation :

Neutralization reaction : It is a type of chemical reaction in which an acid react with a base to give salt and water as a product that means it reacts to give a neutral solution. It is also known as acid-base reaction.

The acid-base reaction will be:

$HClO_3+LiOH\rightarrow LiClO_3+H_2O$

Therefore, the products of the acid-base reaction between $HClO_3$ and LiOH are, $LiClO_3$ and $H_2O$

6 0

3 years ago

Read 2 more answers