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3 years ago

Why is electron capture accompanied by the emission of an X-ray?

Chemistry

1 answer:

marissa [1.9K]3 years ago

8 0

Answer:

During electron capture, an inner electron usually from K shell or L shell combines with proton of the nucleus thereby changing proton to neutron. The process of electron capture is also accompanied by the emission of neutrino. It generally occurs in proton rich nucleus. The capture of electron by the proton creates a hole in the electron shell. The hole created is generally filled by the dropping down of a higher level electron with the emission of X -ray.

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HELP ASAP PLEASAE!!!

N76 [4]

I believe the answer is A. However, I would double check the formula.

4 0

3 years ago

2.38g of black copper(iii) oxide is completely reduced to by hydrogen to give copper and water. What are the number of atoms of

OleMash [197]

Explanation:

here is the answer bae. Feel free to ask for more

6 0

3 years ago

The proper name for a carbohydrate polymer with 2 subunits is

valentina_108 [34]

Carbohydrates are classified in three major categories depending upon the number of sub units joining to form them. These are,

Monosaccharides

Oligosaccharides

Polysachharides

The simplest single units are monosaccharides, if units are ranging between two and twenty they are called oligosaccharides and above twenty joining units they are called polysachharides.

Result:
<span>The proper name for a carbohydrate polymer with 2 subunits is called Oligosachharide in general and Disaccharide in specific.</span>

8 0

4 years ago

In the titration of wine to determine the acid concentration, 10.0 mL of wine was placed in a beaker and diluted with 40.0 mL of

BARSIC [14]

Answer:

0.0042 M is the molarity of tartaric acid in this sample of wine.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is tartaric acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?\\V_1=10.0+40.0 mL=50.0 mL\\n_2=1\\M_2=0.051 M M\\V_2=8.20 mL$

Putting values in above equation, we get:

$2\times M_1\times 50.0 mL=1\times 0.051 M\times 8.20 mL$

$M_1=\frac{1\times 0.051 M\times 8.20 mL}{2\times 50.0 mL}=0.0042 M$

0.0042 M is the molarity of tartaric acid in this sample of wine.

6 0

3 years ago

In the periodic table hydrogen is placed in Group 1A (group 1) and helium is placed in Group 8A (group 18). The most likely reas

Alexus [3.1K]

Answer:

This question appears incomplete

Explanation:

This question appears incomplete because of the absence of options. However, hydrogen is placed in group 1 because it has just one electron in it's outermost shell (which happens to be the only shell it has) just like every other group 1A/group 1 element. While helium is placed in group 8A/group 18 because it has a completely filled outermost shell (which is also the only shell it has) just like every other element in group 8A/group 18.

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3 years ago