Question

Calculating the acceleration of two people pulling a box with same force and angle.

Answer 1

Here as we can see there we be net horizontal force acting on it

$F_x = F_1cos20 + F_2cos20$

also we know that

$F_1 = F_2 = 80 N$

now we will have

$F_x = 2(80cos20)$

$F_x = 150.35 N$

now for net force of box we know

$F_x - F_f = ma$

$150.35 - 100 = ma$

$20a = 50.35$

$a = 2.52 m/s^2$

so acceleration of the box will be 2.52 m/s/s