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galina1969 [7]
3 years ago
14

Calculating the acceleration of two people pulling a box with same force and angle.

Physics
1 answer:
Dmitriy789 [7]3 years ago
7 0

Here as we can see there we be net horizontal force acting on it

F_x = F_1cos20 + F_2cos20

also we know that

F_1 = F_2 = 80 N

now we will have

F_x = 2(80cos20)

F_x = 150.35 N

now for net force of box we know

F_x - F_f = ma

150.35 - 100 = ma

20a = 50.35

a = 2.52 m/s^2

so acceleration of the box will be 2.52 m/s/s

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Question 2 (1 point)
Tju [1.3M]

Answer:

I know someone anwsered but it would be 400M

Explanation:

i initial velocity (u)=10m/s

acceleration (a)=0

time taken (t) =40s

then distance (s)=u t +1/2 a t^2

s= u t +0 (as a is 0)

s= 10 x 40

s= 400M

7 0
3 years ago
Which describes an object’s speed in free fall?
Mrac [35]
"Free fall" is the motion of an object when gravity is the ONLY force
acting on it.

In true 'free fall' the speed of an object increases at a constant rate
for the total duration of the fall.  The rate of increase, on or near the
Earth's surface, is 9.8 meters per second for each second of fall.

True free fall is almost impossible to observe in everyday life, because
whenever we see anything falling, it's almost always falling through air,
so gravity is NOT the only force acting on it.  The friction due to the
motion through air works against the gravitational force.  In many cases,
the result is that the object's speed eventually stops increasing and
becomes constant, at a speed often described with the faux technical,
high-fallutin' sounding phrase "terminal velocity".  It must be understood
that 'terminal velocity' is NOT a property of gravity or of free fall, but is
only a result of falling through some surrounding stuff that interferes with
the process of true 'free fall'.
6 0
4 years ago
Read 2 more answers
Waves inwhich the particles vibrate at right angles to direction is called
liberstina [14]
When the particles<span> of a medium are </span>vibrating at right angles<span> to the </span>direction<span> of energy transport, then the </span>wave<span> is a ____ </span>wave<span>. In transverse </span>waves<span>, </span>particles<span> of the medium </span>vibrate<span> to and from in a </span>direction<span> perpendicular to the </span>direction<span> of energy transport. </span>
5 0
3 years ago
1
Keith_Richards [23]
Yeah I conclude that the answer is A because it need distance but with out charge it would no get that distance so yeah A
5 0
2 years ago
A 5.0 A electric current passes through an aluminum wire of 4.0~\times~10^{-6}~m^2 cross-sectional area. Aluminum has one free e
Serhud [2]

Answer: The electron number density (the number of electrons per unit volume) in the wire is 6.0 \times 10^{28} m^{-3}.

Explanation:

Given: Current = 5.0 A

Area = 4.0 \times 10^{-6} m^{2}

Density = 2.7 g/cm^{3}, Molar mass = 27 g

The electron density is calculated as follows.

n = \frac{density}{mass per atom}\\= \frac{\rho}{\frac{M}{N_{A}}}\\

where,

\rho = density

M = molar mass

N_{A} = Avogadro's number

Substitute the values into above formula as follows.

n = \frac{\rho \times N_{A}}{M}\\= \frac{2.7 g/cm^{3} \times 6.02 \times 10^{23}/mol}{27 g/mol}\\= \frac{16.254 \times 10^{23}}{27} cm^{3}\\= 0.602 \times 10^{23} \times \frac{10^{6} cm^{3}}{1 m^{3}}\\= 6.0 \times 10^{28} m^{-3}

Thus, we can conclude that the electron number density (the number of electrons per unit volume) in the wire is 6.0 \times 10^{28} m^{-3}.

8 0
3 years ago
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