As per energy conservation we know that
Energy enter into the bulb = Light energy + Thermal energy
so now we have
energy enter into the bulb = 100 J
Light energy = 5 J
now from above equation we have
Answer:
Verified that he oscillations are exactly isosynchronous with frequency ω0 = p g/l, independent of the amplitude.
Explanation:
Starting from the first principle for the derivation and to prove that the oscillations are exactly isosynchronous with frequency ω0 = p g/l, independent of the amplitude. The mathematical manipulations was applied, trigonometric identities was also applied.The steps and explanation are shown in the attachment.
Assuming negligible air resistance, the shell travels at a constant horizontal velocity equal to what it had immediately after leaving the barrel. The shell is in the air until hitting the target; the length of this period of time is therefore directly proportional to the distance between the barrel and the target.
The shell hits the target below where it was aimed at for it experiences gravitational pull during its flight. With the barrel pointed "parallel to the ground" the shell shall experience no initial vertical velocity, meaning that it its undergoing a freefall on the vertical direction. and are therefore the respective vertical displacements of the two trials.
The formula below relates the vertical displacement to the gravitational acceleration and the time duration of the freefall :
Let and be the duration of the shell's flight on the first and second trials, respectively; Thus
Answer:
This is your answer
Explanation:
Actually I took this from go ogle