Answer:

- Before solving , You'll have to know - When an object starts from the state of rest , in this case , initial velocity ( u ) = 0
- Notice that we're provided the time ( t ) in minutes. So , first thing we have to do is convert the minutes into seconds. It would be - Time ( t ) = 5 minutes = 5 × 60 sec = 300 sec [ 1 min = 60 sec ]
- Here , We're provided - Initial velocity ( u ) = 0 , Final velocity ( v ) = 60 m / s , Time taken ( t ) = 300 seconds & We're asked to find out the acceleration ( a ) & distance covered by the jeep ( s ) .

- Acceleration is defined as the rate of change of velocity. We know :

- Plug the values & then simplify !

- The acceleration of the jeep is 0.2 m/s²


- Plug the values & then simplify !

- The distance covered by the jeep is 9000 m .
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Give me some answer choices and i will be happy to help
Answer:
The moment of inertia of this sphere is
.
Explanation:
It is given that,
Mass of the sphere, m = 4.8 kg
Radius of the sphere, r = 22 cm = 0.22 m
Tangential force, F = 11.2 N
The moment of inertia of the uniform sphere is given by :



So, the moment of inertia of this sphere is
. Hence, this is the required solution.
Answer:
Proton’s speed, a short time later when it reaches a point of lower potential is 1.4 x 10⁵ m/s
Explanation:
Given;
initial speed of proton, u = 2.5 x 10⁵ m/s
initial potential, V = 1500 V
mass of proton = 1.67 x 10⁻²⁷ kg
Work done, W = eV= ΔK.E = ¹/₂mu²
eV = ¹/₂mu² (J)
where;
e is the charge of the proton in coulombs
V is the electric potential in volts
m is the mass of the proton in kg
u is the speed of the proton in m/s


Therefore, proton’s speed a short time later when it reaches a point of lower potential is 1.4 x 10⁵ m/s