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3 years ago

When it is 32º Farenheit, what is the temperature in degrees Celsius?

Physics

2 answers:

Nastasia [14]3 years ago

7 0

Answer:

The answer is B.

Explanation:

If 212 degrees Fahrenheit is 100 degrees Celsius, then 32 degrees Fahrenheit is 0 degrees Celsius.

just olya [345]3 years ago

4 0

Answer: B

Explanation:

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10. At point A, a runner is jogging 5 m/s. Forty seconds later, at point B

kondaur [170]

Answer:

Deceleration of 0.075m/s²

Explanation:

Given parameters:

Initial velocity = 5m/s

Time = 40s

Final velocity = 2m/s

Unknown:

The jogger's acceleration = ?

Solution:

To solve this problem, we use;

a = $\frac{v - u}{t}$

a is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

a = $\frac{2 - 5}{40}$ = - 0.075m/s²

5 0

3 years ago

At which position is the kinetic energy of a particle executing SHM greatest?

Over [174]

Explanation:

The kinetic energy of a particle in SHM is given by :

$K=\dfrac{1}{2}m\omega^2(A^2-x^2)$

Where

m is the mass of a particle

A is the amplitude

x is the distance

$\omega$ is the angular frequency

The kinetic energy of a particle executing SHM is maximum at its equilibrium position and minimum at a maximum displacement from the equilibrium point.

8 0

2 years ago

Two wires are parallel and one is directly above the other. Each has a length of 50.0 m and a mass per unit length of 0.020 kg/m

ivann1987 [24]

Answer: The time required for the impluse passing through each other is approximately 0.18seconds

Explanation:

Given:

Length,L = 50m

M/L = 0.020kg/m

FA = 5.7×10^2N

FB = 2.5×10^2N

The sum of distance travelled by each pulse must be 50m since each pulse started from opposite ends.

Ca(t) + CB(t) = 50

Where CA and CB are the velocities of the wire A and B

t = 50/ (CA + CB)

But C = Sqrt(FL/M)

Substituting gives:

t = 50/ (Sqrt( FAL/M) + Sqrt(FBL/M))

t = 50/(Sqrt 5.7×10^2/0.02) + (Sqrt(2.5×10^2/0.02))

t = 50 / (168.62 + 111.83)

t = 50/280.15

t = 0.18 seconds

4 0

2 years ago

Read 2 more answers

If the velocity of blood flow in the aorta is normally about 0.32 m/s, what beat frequency would you expect if 4.40-MHz ultrasou

dusya [7]

Answer:

The beat frequency is 0.0019 MHz.

Explanation:

Given that,

Velocity = 0.32 m/s

Frequency = 4.40 MHz

Speed of wave = 1540 m/s

We need to calculate the frequency

Case (I),

Observer is moving away from the source

Using Doppler's effect

$f'=\dfrac{v-v'}{v}f$

Where, v' = speed of observer

Put the value into the formula

$f'=\dfrac{1540-0.32}{1540}\times4.40$

$f'=4.399\ MHz$

Case (II),

Cell is as the source of sound of frequency f' and it moving away from the observer.

Using formula of frequency

$f''=\dfrac{v-v_{s}}{v+v_{s}}\times f$

$f''=\dfrac{1540-0.32}{1540+0.32}\times4.399$

$f''=4.3971\ MHz$

We need to calculate the beat frequency

$\Delta f= f'-f''$

$\Delta f=4.399-4.3971=0.0019\ MHz$

Hence, The beat frequency is 0.0019 MHz.

4 0

3 years ago

How to increase the current in a circuit

ivann1987 [24]

Answer:

So to increase current of the circuit what you can do is :

1. Use conductor of low resistivity, ¶.

2. Use conductor of small length.

3. Use thick wire.

4. Decrease the temperature of the circuit.

5. If operating temprature is high than use semiconductor, because it have negative temprature coefficient.

6. Minimise the circuit losses.

3 0

2 years ago