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DerKrebs [107]
3 years ago
8

When it is 32º Farenheit, what is the temperature in degrees Celsius?

Physics
2 answers:
Nastasia [14]3 years ago
7 0

Answer:

The answer is B.

Explanation:

If 212 degrees Fahrenheit is 100 degrees Celsius, then 32 degrees Fahrenheit is 0 degrees Celsius.

just olya [345]3 years ago
4 0

Answer: B

Explanation:

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An output is a Push or pull _________________________ on the object
Ugo [173]

Answer:

The input force that you use on an inclined plane is the force with which you push or pull an object. The output force is the force that you would need to lift the object without the inclined plane. This force is equal to the weight of the object.

Explanation:

5 0
3 years ago
If 34.7 g of O2 reacts with iron to form 79.34 g of iron oxide, how much iron was used in the reaction?
zhuklara [117]

Answer: B. 44.64 g

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Mass of reactants = mass of iron + mass of oxygen = mass of iron + 34.7 g

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As Mass of reactants = Mass of product

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mass of iron = 44.64 g

Thus 44.64 g of iron was used in the reaction

6 0
3 years ago
Which of the following are true for acceleration?
Fittoniya [83]

The SI unit for acceleration is m/s2 ( D)

6 0
3 years ago
Make a free-body diagram of someone pushing a refrigerator that shows:
adoni [48]

Answer:

head fah ueah ik

Explanation:

5 0
3 years ago
A skier leaves the horizontal end of a ramp with a velocity of 31.0 m/s and lands 156.3 m from the base of a ramp how high is th
BartSMP [9]

<u>Answer:</u>

The height of ramp = 124.694 m

<u>Explanation:</u>

Using second equation of motion,

s = ut + \frac{1}{2}at^2

From the question,

u = 31 m/s; s = 156.3 m, a=0

substituting values

156.3 = 31\times t + 0

t = \frac{156.3}{31 }

= 5.042 s

Similary, for the case of landing

t = 5.042 s; initial velocity, u =0

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Substituting in h = ut + \frac{1}{2}gt^2

h = 0 + \frac{1}{2} \times 9.81 \times (5.042)^2

h = 124.694 m

So height of ramp = 124.694 m

3 0
3 years ago
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