Answer:
35.35 m
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 20 m/s
Angle of projection (θ) = 30°
Acceleration due to gravity (g) = 9.8 m/s²
Range (R) =.?
The range (i.e how far away) of the ball can be obtained as follow:
R = u² Sine 2θ /g
R = 20² Sine (2×30) / 9.8
R = 400 Sine 60 / 9.8
R = (400 × 0866) / 9.8
R = 346.4 / 9.8
R = 35.35 m
Therefore, the range (i.e how far away) of the ball is 35.35 m
Answer:
the assessment is due at 11 you only have 1 hour do it fasst
Explanation:
the assessment is due at 11 you only have 1 hour do it fasst
All are true except the first two.
79 m/s. A stone dropped from the top of the Empire State Building will have a velocity of 79 m/s just before it strikes the ground.
This problem is about free fall, to find the velocity of the stone before it strikes the ground we have to use the equation 
, the initial velocity of the stone is 0 m/s. Then:
Solving the equation above with g = 9.8 m/s², and h = 318.0 m:
≅ 79 m/s
