Answer:
Explanation:
Weight in air = true weight = 250 pounds
density of iron , d = 480 lbs/ft³
density of sea water, d' = 64 lbs/ft³
Volume of iron = mass / density of iron
V = 250 / 480 = 0.521 ft³
Force required to lift = weight of iron in water = Apparent weight of iron
Weight in water = true weight - buoyant force
Weight in water = 250 x g - volume x density of water x g
Weight in water = 250 g - 0.521 x 64 x g
Weight in water = 216.67 g
Weight in water = 216.67 pounds
Thus, the force required to lift the iron is 216.67 pounds.