Answer:

Explanation:
You calculate the energy required to break all the bonds in the reactants.
Then you subtract the energy needed to break all the bonds in the products.
2H₂ + O₂ ⟶ 2H-O-H
Bonds: 2H-H 1O=O 4H-O
D/kJ·mol⁻¹: 436 498 464

When a glacier has equal snow accumulation and wastage. Hope this helps!
2Cu(NO3)2 ----------> 2CuO (s) +4NO2 (g) + O2(g)
9.378g=0.05moles
no of moles = weight / MW = 9.378/187.56 = 0.05moles
as per the above reaaction 2moles of Cu(NO3)2 can produce 4moles of N2
0.05moles Cu(NO3)2 can produce (0.05*4)/2 = 0.1moles of N2
and 2moles of Cu(NO3)2 can produce 1moles of O2
0.05moles Cu(NO3)2 can produce (0.05*1)/2 = 0.025moles of O2
Total moles of gas i.e., N2 and O2 =0.1+0.025 = 0.125moles
From PV = nRT
V = nRT/ P = 0.125*0.0821*273 = 2.80166Lit option is correct
Each mole has 6.02 x10^23 atoms so they have same atoms
<span>XY4Z2-->Square planar (Electron domain geometry: Octahedral) sp3d2
XY4Z-->Seesaw (Electron domain geometry: Trigonal bipyramidal) sp3d
XY5Z-->Square pyramidal (Electron domain geometry: Octahedral) sp3d2
XY2Z3-->Linear (Electron domain geometry: Trigonal bipyramidal) sp3d
XY2Z-->Bent (Electron domain geometry: Trigonal planar) sp2
XY3Z-->Trigonal pyramidal (Electron domain geometry: Tetrahedral) sp3
XY2Z2-->Linear (Electron domain geometry: Tetrahedral) sp3
XY3Z2-->T shaped (Electron domain geometry: Trigonal bipryamidal) sp3d
XY2-->Linear (Electron domain geometry: Linear) sp
XY3 Trigonal planar (Electron geometry: Trigonal planar) sp2
XY4-->Tetrahedral (Electron domain geometry: tetrahedral) sp3
XY5-->Trigonal bipyramidal (Electron domain geometry: Trigonal bipyramidal) sp3d
XY6-->Octahedral (Electron domain geometry: Octahedral) sp3d2</span>