Where photosynthesis takes place?

A gas has a volume of 10 liters under a pressure of 745 mm of Hg.

aksik [14]

Answer:

Volume is 10.35 L

Explanation:

we are given;

Initial volume v₁ is 10 L
Initial pressure, P₁ as 745 mmHg
New pressure ,P₂ as 720 mmHg

We are required to determine the new volume, V₂

We are going to use the Boyle's law;

According to Boyle's law the volume and the pressure of a fixed mass of a gas are inversely proportional at a constant temperature.

Therefore;

P₁α 1/V

That is;

P = k/V

k = PV

At different conditions;

P₁V₁ = P₂V₂

Rearranging the formula;

V₂ = P₁V₁ ÷ P₂

Thus;

New volume = (10 L× 745 mmHg) ÷ 720 mmHg

= 10.35 L

Thus, the new volume of the gas at the new pressure is 10.35 L

8 0

3 years ago

50.0 mL of a solution of HCl is combined with 100.0 mL of 1.05M NaOH in a calorimeter. The reaction mixture is initially at 22.4

VikaD [51]

Answer:

2.1 M is the molarity of the HCl solution.

Explanation:

$HCl+NaOH\rightarrow H_2O+NaCl$

Molarity of HCl solution = $M_1=?$

Volume of HCl solution = $V_1=50.0mL$

Ionizable hydrogen ions in HCl = $n_1=1$

Molarity of NaOH solution = $M_2=1.05 M$

Volume of NaOH solution = $V_2=100.0 mL$

Ionizable hydroxide ions in NaOH = $n_2=1$

$n_1M_1V_1=n_2M_2V_2$ (neutralization )

$M_1=\frac{M_2V_2}{V_1}=\frac{1.05M\times 100.0 mL}{50.0 mL}$

$M_1=2.1 M$

2.1 M is the molarity of the HCl solution.

3 0

3 years ago

calculate the mass of sodium hydroxide you would need to neutralize a solution containing 7.3g of hydrochloric acid

Mashcka [7]

Molar mass of NaOH = 23 + 16 + 1 = 40.0 g/mol

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

NaOH + HCl = NaCl + H2O

1*40 g NaOH ------> 1*36.5 g HCl
g NaOH -------> 7.3 g HCl

36.5 g = 40 * 7.3

36.5 g = 292

mass ( NaOH ) = 292 / 36.5

mass ( NaOH ) = 8.0 g of NaOH

hope this helps!.

4 0

3 years ago

Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction: P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH

Pie

Answer: -1835 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

$PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)$ $\Delta H_1=+157kJ$ (1)