Answer: quatrain
Explanation:
Reading the Shakespeare's "Sonnet 100", we can infer that the underlined section is referred to as a quatrain.
The quatrain simply refers to a type of stanza that is made up of four lines. For example, based on the information given, we can deduce that the rhyme scheme for the second quatrain is given as cdcd.
Answer:
7.9 kilometers per second
Explanation:
Answer:
a
Hardness Test
b
The available hardness test are
- Rockwell hardness test
- Vicker's hardness test
- knoop test
- scratch test
- Brinell hardness test e.t.c
I would suggest Rockwell test because
- It has good accuracy
- In this test loads can be applied in 2 stages hence better results are obtained
- it saves time because it testing are faster
c
Well the following would be the reasons for low hardness value
- It could be because the steel used has a low percentage of carbon
- it could also result from the quenching medium used (e.g water , brine solution e.t.c)
d
In order to solve this problem here are the following ways
- When selecting steel the ones with a carbon percentage 0.3% to 0.8% should be selected
- When quenching the quenching medium should be brine solution
Explanation:
The reason why the answer to question is hardness test is because the heat treatment was carried out to obtain hardness so if it is great then the heat treatment is good
Answer:
a₁= 1.98 m/s² : magnitud of the normal acceleration
a₂=0.75 m/s² : magnitud of the tangential acceleration
Explanation:
Formulas for uniformly accelerated circular motion
a₁=ω²*r : normal acceleration Formula (1)
a₂=α*r: normal acceleration Formula (2)
ωf²=ω₀²+2*α*θ Formula (3)
ω : angular velocity
α : angular acceleration
r : radius
ωf= final angular velocity
ω₀ : initial angular velocity
θ : angular position theta
r : radius
Data
r =0.4 m
ω₀= 1 rad/s
α=0.3 *θ , θ= 2π
α=0.3 *2π= 0,6π rad/s²
Magnitudes of the normal and tangential components of acceleration of a point P on the rim of the disk when theta has completed one revolution.
We calculate ωf with formula 3:
ωf²= 1² + 2*0.6π*2π =1+2.4π ²= 24.687
ωf=
=4.97 rad/s
a₁=ω²*r = 4.97²*0.4 = 1.98 m/s²
a₂=α*r = 0,6π * 0.4 = 0.75 m/s²
