Answer:
B. To accurately measure spark advance, use a timing light that incorporates an
ignition advance meter. The spark advance cannot be determined by listening to the way the engine sounds.
Answer:
The maximum power that can be generated is 127.788 kW
Explanation:
Using the steam table
Enthalpy at 20 bar = 2799 kJ/kg
Enthalpy at 2 bar = 2707 kJ/kg
Change in enthalpy = 2799 - 2707 = 92 kJ/kg
Mass flow rate of steam = 5000 kg/hr = 5000 kJ/hr × 1 hr/3600 s = 1.389 kg/s
Maximum power generated = change in enthalpy × mass flow rate = 92 kJ/kg × 1.389 kg/s = 127.788 kJ/s = 127.788 kW
Answer:
a) V(t) = Ldi(t)/dt
b) If current is constant, V = 0
Explanation:
a) The voltage, V(t), across an inductor is proportional to the rate of change of the current flowing across it with time.
If V represents the Voltage across the inductor
and i(t) represents the current across the inductor in time, t.
V(t) ∝ di(t)/dt
Introducing a proportionality constant,L, which is the inductance of the inductor
The general equation describing the voltage across the inductor of inductance, L, as a function of time when a current flows through it is shown below.
V(t) = Ldi(t)/dt ..................................................(1)
b) If the current flowing through the inductor is constant i.e. does not vary with time
di(t)/dt = 0 and hence the general equation (1) above becomes
V(t) = 0
The answer is c. 4 seconds
