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Darina [25.2K]
3 years ago
5

In a typical chemical reaction, the subscript for a particular atom is written...

Chemistry
1 answer:
Lerok [7]3 years ago
6 0
The subscript in a chemical reaction cannot be changed. Its written like this:-

Ca₆

That means Ca = 6
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What is the SI base unit for length?
sp2606 [1]

The SI base unit for length is meter.

In order to make smaller measurements, you can use the centi-, milli-, micro-, etc. prefixes.

When you want to reference larger measurements, you can use the kilo-, mega-, giga- and prefixes such as those.

5 0
3 years ago
What changes if the degree (amount) of intermolecular bonds of a substance are changed?
elixir [45]
<h2>Answer:</h2>

The correct answers are;

volume of a substance

density of a substance

  • The volume and the density of the substance depend on inter molecular forces of the substance. So, when we will change the degree of inter molecular forces, whether decrease it or increase it, it will affect the volume and density of a substance.
7 0
4 years ago
Read 2 more answers
A. 20 moles of NH3 are needed to produce how many moles of H2O?
tiny-mole [99]

a. 30 moles of H₂O

b. 2.33 moles of N₂

<h3>Further explanation</h3>

Given

a. 20 moles of NH₃

b. 3.5 moles of O₂

Required

a. moles of H₂O

b. moles of N₂

Solution

Reaction

4NH₃+3O₂⇒2N₂+6H₂O

a. From the equation, mol ratio NH₃ : H₂O = 4 : 6, so mol H₂O :

=6/4 x mol NH₃

= 6/4 x 20 moles

= 30 moles

b. From the equation, mol ratio N₂ : O₂ = 2 : 3, so mol N₂ :

=2/3 x mol O₂

= 2/3 x 3.5 moles

= 2.33 moles

7 0
3 years ago
PLSSSSS ANSWERRRR?????
vredina [299]

Answer:steeper

Explanation:if it was me thats what i would pick

7 0
3 years ago
A hypothetical metal crystallizes with the face-centered cubic unit cell. The radius of the metal atom is 234 picometers and its
AleksAgata [21]

Answer:

\delta=101.13 g/cm^3

Explanation:

As can be seen in the Figure in a face-centered cubic unit cell you have:

  • Six halves of atoms
  • Eight 1/8 of atom (1 in each corner)

In total:

n_{atom}=6*0.5+8*\frac{1}{8}=4 atoms

Now, each side of the cell is 234 picometers (2.34e-8 cm) long

V_{cell}=L^3=(2.34e^{-8} cm)^3

V_{cell}=1.28*10^{-23}cm^3

Atoms per cm3:

n=\frac{4 atoms}{1.28*10^{-23}cm^3}

n=3.12*10^{23} atoms/cm^3

Expressing in mass:

\delta=3.12*10^{23} atoms/cm^3* \frac{1 mol}{6.022*10^{23}}*195.08 g/mol

\delta=101.13 g/cm^3

6 0
3 years ago
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