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lys-0071 [83]
3 years ago
11

Please I don’t get this at all someone help

Chemistry
1 answer:
ohaa [14]3 years ago
6 0
I think it’s 7.41 because you count up all the atoms and find out how many are x (the large grey ones) and you do 2/27 x 100 which gives you 7.41 :) (sorry if i counted wrong it’s kinda hard)
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Whose work is credited with being the beginning of the modern atomic theory​
Damm [24]
Democritus (460-370 BC) was a Greek philosopher who theorized that all matter could be reduced to particles that could not be divided, which he described as “atomos.”

John Dalton (1766-1844) Proposed the atomic theory.

7 0
3 years ago
Which correctly describes the reaction between potassium and excess water?
nika2105 [10]
Balanced chemical reaction: 2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g).

KOH is inorganic compound p<span>otassium hydroxide, a strong base.
H</span>₂ is hydrogen gas.
In balanced chemical reaction number of atoms on both side of chemical reaction must be same. There are two potassium atoms, four hydrogen atoms and two oxygen atoms on both side of reaction.
7 0
3 years ago
The maximum amount of nickel(II) cyanide that will dissolve in a 0.220 M nickel(II) nitrate solution is...?
sweet [91]

Answer : The maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

Explanation :

The solubility equilibrium reaction will be:

                       Ni(CN)_2\rightleftharpoons Ni^{2+}+2CN^-

Initial conc.                        0.220       0

At eqm.                             (0.220+s)   2s

The expression for solubility constant for this reaction will be,

K_{sp}=[Ni^{2+}][CN^-]^2

Now put all the given values in this expression, we get:

3.0\times 10^{-23}=(0.220+s)\times (2s)^2

s=5.84\times 10^{-12}M

Therefore, the maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

7 0
3 years ago
Does percent error measure accuracy or precision?
Nesterboy [21]

Answer:

Precision

Explanation:

It figures out how close all of the data numbers are.

4 0
3 years ago
Read 2 more answers
Calculations
Black_prince [1.1K]

Answer:

Theoretical yield: 2.75g of paranitroaniline

Percentage yield: 54.5%

Explanation:

In strong-acid medium, acetanilide (Molar mass: 135.16g/mol) reacts producing para-nitroaniline (138.12g/mol) in a 1/1 reaction.

Theoretical yield of para-nitroaniline is the mass produced assuming a yield of 100%. That is:

2.7g acetanilide × (1mol / 135.16g) = 0.020 moles of acetanilide.

Assuming a yield of 100% are 0.020 moles of paranitroaniline. Theoretical yield is:

0.020 moles × (138.12g / mol) =

<h3>Theoretical yield: 2.75g of paranitroaniline</h3><h3 />

Percentage yield is:

(Actual yield / theoretical yield) × 100

Actual yield was 1.5g and percentage yield will be:

Percentage yield: (1.5g / 2.75g) × 100

<h3>Percentage yield: 54.5%</h3>

8 0
3 years ago
Read 2 more answers
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