Answer:
Density of Radon is 5.44 g/.
Explanation:
Given data:
Temperature of gas = 100°C (273+100 = 373 K)
Pressure of gas = 0.75 atm
Density of gas = ?
Solution:
First of all we will derive the formula.
We know that,
PV = nRT
and
n = m/M (m = mass, M = molar mass)
PV = (m/M) RT
PVM = (m/M) RT ×M
PVM = mRT
PVM/V = mRT/V
PM = dRT (m/V = d)
Now we will put the values in formula:
Molar mass of Radon is 222 g/mol .
0.75 atm ×222 g/mol = d× 0.0821 atm.L/mol.K ×373 K
166.5 atm.g/mol = d×30.62 atm.L/mol
d = 166.5 atm.g/mol / 30.62 atm.L/mol
d = 5.44 g/L
Answer:
Lithium nitrate
Explanation:
Lithium nitrate is an inorganic compound with the formula LiNO3. It is the lithium salt of nitric acid (an alkali metal nitrate).
Answer:
Explanation:
Hello,
In this case, for the given combustion process, we can compute the present moles of carbon atoms by considering that the only product containing carbon is CO2, thus, we have:
Next, we compute the moles of hydrogen that is present at the water only as a product:
Then, we compute the moles of oxygen by considering the oxygen present in both the CO2 and H2O and the initial sample:
Now, we divide the moles of C, H and O by the moles of O since they are lower amount, in order to compute the subscript in the empirical formula:
But the smallest whole number is:
Regards.
- A buffer solution resists the change in pH after the addition of small amounts of acid or base to it.
- The given buffer solution is NaHCO₃ (acid) + Na₂CO₃ (conjugate base).
- NaHCO₃ contains HCO₃⁻ and Na⁺ ions. Na₂CO₃ contains Na⁺ and CO₃²⁻ ions. Na⁺ ions do not show any effect on the pH of a solution.
Therefore, HCO₃⁻ and CO₃²⁻ are responsible for the buffer action.
HCO₃⁻ is the acidic component of the buffer. It neutralizes the small amounts of base added to it producing an equivalent amount of the conjugate base CO₃²⁻.
HCO₃⁻(aq) + OH⁻(aq) → CO₃²⁻(aq) + H₂O(l)
Acid conjugate base
CO₃²⁻ is the basic component if the buffer. It neutralizes the small amounts of acid added to it producing an equivalent amount of the conjugate acid HCO₃⁻
CO₃²⁻(aq) + H₃O⁺(aq) → HCO₃⁻(aq) + H₂O(l)
Base Conjugate acid
- Therefore, even after the addition of a small amount of acid or base to the buffer, pH remains unchanged.