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3 years ago

6) Which choice is equivalent to the expression shown?-5(2r - 6p) + 3(4r-3p)

Mathematics

1 answer:

makvit [3.9K]3 years ago

3 0

Answer:

3(4r-3p)

Step-by-step explanation:

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A: HL<br> B: ASA<br> C: SSS<br> D: SAS

evablogger [386]

Answer:

D: SAS

Step-by-step explanation:

6 0

3 years ago

John accepted a reduction of 15% on his salary when his company was not doing well. Now his company's financial position has imp

o-na [289]

To reverse a percentage decrease you divide it by the decrease (+ 100%)
For example we will pick the number, 100, which is decreased by 15% to 85.

To make 85 back to 100 we divide it by the decrease (1-0.15):
85 / 0.85 = 100

To find out how much 85 increased to get back to 100, we do:
15 / 85 = 0.1765 = %17.65

15 is the reduction/difference, and 85 is the with reduction total.

Because percentages stay the same, this is applicable to any numbers, from this, we know that whenever something is reduced by 15% - when restored to it's original is increased by %17.65

The answer is %17.65

6 0

3 years ago

Suppose you have a score of 35 in a game. On your next turn, you get a 50-point penalty. What is your new score?

Vsevolod [243]

35-50. = -15. You are 15 points in the hole

4 0

3 years ago

Winning the jackpot in a particular lottery requires that you select the correct four numbers between 1 and 42 and, in a separa

NARA [144]

Answer:

$\dfrac{1}{3,357,900}$

Step-by-step explanation:

There are

$C^{42}_4=\dfrac{42!}{4!(42-4)!}=\dfrac{42!}{4!\cdot 38!}=\dfrac{38!\cdot 39\cdot 40\cdot 41\cdot 42}{2\cdot 3\cdot 4\cdot 38!}=39\cdot 10\cdot 41\cdot 7=111,930$

different ways to select the four numbers between 1 and 42. Only one of this ways is correct (successful to win).

There are 30 different ways select the single number between 1 and 30. Only one of them is correct.

The probability of winning the jackpot is

$\dfrac{1}{111,930}\cdot \dfrac{1}{30}=\dfrac{1}{3,357,900}$

4 0

3 years ago

Read 2 more answers

In a sociology class there are 1414 sociology majors and 1111 non-sociology majors. 33 students are randomly selected to present

saul85 [17]

Answer: $0.4065$

Step-by-step explanation:

Given : In a sociology class there are 14 sociology majors and 11 non-sociology majors.

Total students = 14+11=25

Number of students are randomly selected = 3

Then, the number of ways to select 3 students from 25 students :-

$^{25}C_3=\dfrac{25!}{(25-3)!3!}=\dfrac{25\times24\times23\times22!}{22!3!}\\\\=2300$

Number of ways to select at least 2 of the 3 students re non-sociology majors :-

$^{14}C_1\times^{11}C_2+^{14}C_0\times ^{11}C_{3}\\\\=(14)\times\dfrac{11!}{2!(11-2)!}+(1)\times\dfrac{11!}{3!(11-3)!}\\\\=(14)(11\times5)+\dfrac{11\times10\times9}{6}\\\\=770+165=935$

The probability that at least 2 of the 3 students selected are non-sociology majors will be :-

$\dfrac{935}{2300}=0.40652173913\approx0.4065$

8 0

3 years ago

6) Which choice is equivalent to the expression shown?-5(2r - 6p) + 3(4r-3p)​

6) Which choice is equivalent to the expression shown?-5(2r - 6p) + 3(4r-3p)