Answer:
Step-by-step explanation:
33)
Chord - FE
Secant - GE
Diameter - FE
Radius - CG, CF , CE
Point of tangency - D
34
Chord - JL
Secant - MN
Diameter - JL
Radius - RK , JK , KL
Point of tangency - U
35)Chord - PN
Secant - LM
Diameter - PN
Radius - RQ, QP, QN
Point of tangency - K
Answer:
The solution for the given expression x ix 6.
Step-by-step explanation:
Solution:
Step 1: Adding (-4x) on both sides
Step 2: Adding (5) on both sides:
The solution for the given expression x ix 6.