What organisms appeared on Earth First?
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Compounds which on dissolving in water gets completely dissociates into its ions are known as strong electrolytes whereas compounds which on dissolving in water gets partially dissociates into its ions are known as weak electrolytes.
Substances which gives solution on dissolving in water and do not dissociates into ions also does not conduct electric current are known as nonelectrolyte.
- Hydrochloric acid,
On adding (strong acid) in water, it will completely dissociates into ions (
and
) and thus, it is a strong electrolyte.
- Sodium hydroxide,
On adding (strong base) in water, it will completely dissociates into ions (
and
) and thus, it is a strong electrolyte.
- Formic acid,
On adding (weak acid) in water, it will partially dissociates into ions (
and
) and thus, it is a weak electrolyte.
- Methyl amine,
On adding (weak base) in water, it will partially dissociates into ions (
and
) and thus, it is a weak electrolyte.
- Potassium chloride,
On adding in water, it will completely dissociates into ions (
and
) and thus, it is a strong electrolyte.
- Ethanol,
On adding in water, it will not dissociates into ions and thus, it is a nonelectrolyte.
- Sucrose,
On adding in water, it will not dissociates into ions and thus, it is a nonelectrolyte.
Answer:
The option closest to the percentage yield is option;
d. 81.1
Explanation:
The given chemical equation of the reaction is presented as follows;
CaO (s) + H₂O (l) → Ca(OH)₂
The mass of CaO in the experiment, m = 2.00 g
The volume of water with which the CaO was reacted = Excess volume of water
Number of moles = Mass/(Molar mass)
The mass of Ca(OH)₂ recovered, actual yield = 2.14 g
The molar mass of CaO = 56.0774 g/mol
The number of moles of CaO in the reaction, n₁ = 2.00 g/(56.0774 g/mol ≈ 0.036 moles
The molar mass of Ca(OH)₂ = 74.093 g/mol
The number of moles of Ca(OH)₂ in the reaction, n₂ = 2.14 g/(74.093 g/mol) ≈ 0.029 moles
From the given chemical reaction, one mole of CaO reacts with one mole of H₂O to produce one mole of Ca(OH)₂
Therefore, 0.036 moles of CaO will produce 0.036 moles of Ca(OH)₂
Mass = Number of moles × Molar mass
The mass of 0.036 moles of Ca(OH)₂ ≈ 0.036 moles × 74.093 g/mol = 2.667348 grams
∴ The theoretical yield of Ca(OH)₂ = 2.667348 grams
The percentage yield = (2.14 g)/(2.667348 grams) × 100 = 80.23%
Therefore, the option which is closest is option d. 81.1.