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SVEN [57.7K]
3 years ago
10

One consequence of Newton's third law of motion is that __________. A. every object that has mass has inertia B. a force acting

upon an object increases that objects acceleration C. all actions have equal and opposite reactions D. none of the above
Physics
2 answers:
bazaltina [42]3 years ago
7 0

Answer:

C. All actions have an equal and opposite reaction.

Explanation:

Arlecino [84]3 years ago
7 0

Answer: the answer is C

Explanation: just took test made 100%

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Objects 1 and 2 attract each other with a electrostatic force of 72.0 units. If the distance separating objects 1 and 2 is chang
qaws [65]

Answer:

288.0 units; that is the electrostatic force of attraction become quadruple of its initial value.

Explanation:

If all other parameters are constant,

Electrostatic Force of attraction ∝ (1/r²)

F = (k/r²) = 72.0

If r₁ = r/2, what happens to F₁

F₁ = (k/r₁²) = k/(r/2)² = (4k/r²) = 4F = 4 × 72 = 288.0 units

5 0
3 years ago
Read 2 more answers
What matches ????????????????
dangina [55]

Answer:

1st: Radiation

2nd: Conduction

3rd: Convection

Explanation:

I actually learned this before in school. Yay

8 0
3 years ago
What is the minimum coeffecient of static friction μmin required between the ladder and the ground so that the ladder does not s
mars1129 [50]

Answer:

\mu = \frac{1}{2tan\theta}

Explanation:

let the ladder is of mass "m" and standing at an angle with the ground

So here by horizontal force balance we will have

\mu N_1 = N_2

by vertical force balance we have

N_1 = mg

now by torque balance about contact point on ground we will have

mg(\frac{L}{2}cos\theta) = N_2(L sin\theta)

so we will have

N_2 = \frac{mg}{2tan\theta}

now from first equation we have

\mu (mg) = \frac{mg}{2tan\theta}

\mu = \frac{1}{2tan\theta}

3 0
3 years ago
Use the law of conservation of energy (assume no friction nor air resistance) to determine the kinetic and potential energy at t
slava [35]

Answer:

Part A

1) At the starting point, we have;

PE = 40,000 J

2) PE = 0 J, KE = 40,000 J

3) KE = 20,000 J

4) PE = 15,000 J

5) KE = 32,500 J

6) KE = 40,000 J, PE = 0 J

7) KE = 35,000 J

8) KE = 40,000 J, PE = 0 J

Part B

The total Mechanical Energy = ME = 40,000 J

At the final point, we have;

ME = KE + PE = 40,000 J + 0 J = 40,000 J

Explanation:

Part A

By the law of conservation of energy, we have;

ME = PE + KE

Where;

ME = The total Mechanical Energy of the system

PE = The Potential Energy of the system

KE = The Kinetic Energy of the system

Where there is no friction, we have;

At the final stage, KE = 40,000 J. PE = 0 J

Therefore, ME = PE + KE = 40,000 J + 0 J = 40,000 J

1) At the starting point, we have;

KE = 0 J, therefore, PE = ME - KE = 40,000 J - 0 J = 40,000 J

2) At the bottom of the roller coaster, at the same level the PE is taken as PE = 0 J at the final stage, we have;

PE = 0 J, therefore, KE = ME - PE = 40,000 J - 0 J = 40,000 J

3) Where PE = 20,000 J, KE = ME - PE = 40,000 J - 20,000 J = 20,000 J

4) Where KE = 25,000 J, PE = ME - KE = 40,000 J - 25,000 J = 15,000 J

5) Where PE = 7,500 J, KE = ME - PE = 40,000 J - 7,500 J = 32,500 J

6) At the bottom KE = 40,000 J, PE = 0 J

7) Where PE = 5,000 J, KE = ME - PE = 40,000 J - 5,000 J = 35,000 J

8) KE = 40,000 J, PE = 0 J

Part B

The given that there is no friction nor air resistance, the total Mechanical Energy, ME, is constant and equal to the sum of the Potential Energy, PE and the Kinetic Energy, KE, as follows;

ME = KE + PE

At the final point, we have;

ME = 40,000 J + 0 J = 40,000 J

The total Mechanical Energy = ME = 40,000 J

8 0
2 years ago
What particles are found in the area surrounding the necleus
Harlamova29_29 [7]
The subatomic particles found in the area surrounding the nucleus of an atom are called electrons.
6 0
3 years ago
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