I was going to beg off until tomorrow, but this one is nothing like those others. Why, at only 40km/hr, we can ignore any relativistic correction, and just go with Newton.
To put a finer point on it, let's give the car a direction. Say it's driving North.
a). From the point of view of the car, its driver, and passengers if any, the pole moves past them, heading south, at 40 km/hour .
b). From the point of view of the pole, and any bugs or birds that may be sitting on it at the moment, the car and its contents whiz past them, heading north, at 40 km/hour.
c). A train, steaming North at 80 km/hour on a track that exactly parallels the road, overtakes and passes the car at just about the same time as the drama in (a) and (b) above is unfolding.
The rail motorman, fireman, and conductor all agree on what they have seen. From their point of view, they see the car moving south at 40 km/hr, and the pole moving south at 80 km/hr.
Now follow me here . . .
The car and the pole are both seen to be moving south. BUT ... Since the pole is moving south faster than the car is, it easily overtakes the car, and passes it . . . going south.
That's what everybody on the train sees.
==============================================
Finally ... since you posed this question as having something to do with your fixation on Relativity, there's one more question that needs to be considered before we can put this whole thing away:
You glibly stated in the question that the car is driving along at 40 km/hour ... AS IF we didn't need to know with respect to what, or in whose reference frame. Now I ask you ... was that sloppy or what ? ! ?
Of course, I came along later and did the same thing with the train, but I am not here to make fun of myself ! Only of others.
The point is . . . the whole purpose of this question, obviously, is to get the student accustomed to the concept that speed has no meaning in and of itself, only relative to something else. And if the given speed of the car ...40 km/hour ... was measured relative to anything else but the ground on which it drove, as we assumed it was, then all of the answers in (a) and (b) could have been different.
And now I believe that I have adequately milked this one for 50 points worth.
A compound is made up of two or more of atoms that are bonded together with each other via a chemical bonding. It is possible to break the compounds into separate smaller components by the process of chemical reaction. One very simple example of compound is water as it is made of two atoms of hydrogen and one atom of oxygen. Whenever atoms are joined together to create a compound, the atoms definitely loose their individual atomic properties. Other very commonly found compound is carbon dioxide. It is made up of one atom of carbon and two atoms of oxygen.
The given question is incomplete. The complete question is as follows.
A 75-g bullet is fired from a rifle having a barrel 0.540 m long. Choose the origin to be at the location where the bullet begins to move. Then the force (in newtons) exerted by the expanding gas on the bullet is , where x is in meters. Determine the work done by the gas on the bullet as the bullet travels the length of the barrel.
Explanation:
We will calculate the work done as follows.
W =
=
=
= 7560 + 1458 - 1364.69
= 7653.31 J
or, = 7.65 kJ (as 1 kJ = 1000 J)
Thus, we can conclude that the work done by the gas on the bullet as the bullet travels the length of the barrel is 7.65 kJ.
