I was going to beg off until tomorrow, but this one is nothing like those others. Why, at only 40km/hr, we can ignore any relativistic correction, and just go with Newton.
To put a finer point on it, let's give the car a direction. Say it's driving North.
a). From the point of view of the car, its driver, and passengers if any, the pole moves past them, heading south, at 40 km/hour .
b). From the point of view of the pole, and any bugs or birds that may be sitting on it at the moment, the car and its contents whiz past them, heading north, at 40 km/hour.
c). A train, steaming North at 80 km/hour on a track that exactly parallels the road, overtakes and passes the car at just about the same time as the drama in (a) and (b) above is unfolding.
The rail motorman, fireman, and conductor all agree on what they have seen. From their point of view, they see the car moving south at 40 km/hr, and the pole moving south at 80 km/hr.
Now follow me here . . .
The car and the pole are both seen to be moving south. BUT ... Since the pole is moving south faster than the car is, it easily overtakes the car, and passes it . . . going south.
That's what everybody on the train sees.
==============================================
Finally ... since you posed this question as having something to do with your fixation on Relativity, there's one more question that needs to be considered before we can put this whole thing away:
You glibly stated in the question that the car is driving along at 40 km/hour ... AS IF we didn't need to know with respect to what, or in whose reference frame. Now I ask you ... was that sloppy or what ? ! ?
Of course, I came along later and did the same thing with the train, but I am not here to make fun of myself ! Only of others.
The point is . . . the whole purpose of this question, obviously, is to get the student accustomed to the concept that speed has no meaning in and of itself, only relative to something else. And if the given speed of the car ...40 km/hour ... was measured relative to anything else but the ground on which it drove, as we assumed it was, then all of the answers in (a) and (b) could have been different.
And now I believe that I have adequately milked this one for 50 points worth.
The one that will change the velocity of a periodic wave is : B. Changing the medium of the wave Waves is always determined by the properties of the medium, which means that changing the medium will change the velocity of the wave
Where represent the force for each of the 5 cases presented on the figure attached.
Explanation:
For this case the figure attached shows the illustration for the problem
We have an inverse square law with distance for the force, so then the force of gravity between Earth and the spaceship is lower when the spaceship is far away from Earth.
Th formula is given by:
Where G is a constant
represent the mass for the earth
represent the mass for the spaceship
represent the radius between the earth and the spaceship
For this reason when the distance between the Earth and the Spaceship increases the Force of gravity needs to decrease since are inversely proportional the force and the radius, and for the other case when the Earth and the spaceship are near then the radius decrease and the Force increase.
Based on this case we can create the following rank:
Where represent the force for each of the 5 cases presented on the figure attached.
