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baherus [9]
3 years ago
12

As Aubrey watches this merry-go-round for a total of 2 minutes, she notices the black horse pass by 15 times. What is the period

of the black horse?
Physics
2 answers:
marishachu [46]3 years ago
8 0
2 min = 120 sec

120/15 = 8

The black horse represents 8 seconds.
Wewaii [24]3 years ago
5 0

Answer:

8 seconds

Explanation:

The time taken by the merry go round to complete one round is called time period.

Number of rounds = 15

Time taken = 2 minutes = 2 x 60 = 120 second

15 rounds are completetd in 120 seconds

1 round completed in 120 / 15 = 8 seconds

So, the time period is 8 seconds.

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What is the charge on 1.0 kg of protons? (e = 1.60 × 10-19 c, mproton = 1.67 × 10-27 kg)?
Andru [333]
First, we need to find the number of protons, which is the total mass divided by the mass of one proton:
N= \frac{m}{m_p}= \frac{1.0 kg}{1.67 \cdot 10^{-27} kg}=6.0 \cdot 10^{26} protons

Then, the total charge is the number of protons times the charge of a  single proton:
Q=Ne = 6.0 \cdot 10^{26}\cdot 1.60 \cdot 10^{-19} C=9.6 \cdot 10^7 C
8 0
3 years ago
Read 2 more answers
The layer of earth that has the lightest elements is the
Sonja [21]
If I remember correctly (from my studies long time ago) the layers are from the outer to the center:
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8 0
3 years ago
(a) When a battery is connected to the plates of a 8.00-µF capacitor, it stores a charge of 48.0 µC. What is the voltage of the
frosja888 [35]

Answer:

a.6 V

b.24 V

Explanation:

We are given that

a.C=8\mu F=8\times 10^{-6} F

1\mu =10^{-6}

Q=48\mu C=48\times 10^{-6} C

We know that

V=\frac{Q}{C}

Using the formula

V=\frac{48\times 10^{-6}}{8\times 10^{-6}}=6 V

b.Q=192\mu C=192\times 10^{-6} C

V=\frac{192\times 10^{-6}}{8\times 10^{-6}}=24 V

8 0
2 years ago
Juan compró un carro que dicen que es muy rápido. Cuándo lo probó recorrió una distancia de 4500m en tan solo 5 min. ¿Qué veloci
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Answer:

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4 0
3 years ago
An electric field of magnitude 2.35 V/m is oriented at an angle of 25.0° with respect to the positive z-direction. Determine the
zzz [600]

Answer:

The magnitude of the electric flux is 3.53\ N-m^2/C

Explanation:

Given that,

Electric field = 2.35 V/m

Angle = 25.0°

Area A= 1.65 m^2

We need to calculate the flux

Using formula of the magnetic flux

\phi=E\cdot A

\phi = EA\cos\theta

Where,

A = area

E = electric field

Put the value into the formula

\phi=2.35\times1.65\times\cos 25^{\circ}

\phi=2.35\times1.65\times0.91

\phi=3.53\ N-m^2/C

Hence, The magnitude of the electric flux is 3.53\ N-m^2/C

8 0
3 years ago
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