Answer:
-0.00152 V
Explanation:
Parameters given:
Diameter of the loop = 11 cm = 0.11m
Rate of change of magnetic field, dB/dt = 0.16 T/s
Radius of the loop = 0.055m
The area of the loop will be:
A = pi * r²
A = 3.142 * 0.055²
A = 0.0095 m²
The EMF induced in a loop of wire due to the presence of a changing magnetic field, dB, in a time interval, dt, is given as:
EMF = - N * A * dB/dt
In this case, there's only one loop, so N = 1.
Therefore:
EMF = -1 * 0.0095 * 0.16
EMF = -0.00152 V
The negative sign indicates that the current flowing through the loop acts opposite to the change in the magnetic field.
Answer:
<h2>The pin's final velocity is 5m/s</h2>
Explanation:
Step one:
given data
mass of ball m1=5kg
initial velocity of ball u1=10m/s
mass of pin m2=2kg
initial velocity of pin u2= 0m/s
final velocity of ball v2=8m/s
final velocity of pin v2=?
Step two:
The expression for elastic collision is given as
m1u1+m2u2=m1v1+m2v2
substituting we have
5*10+2*0=5*8+2*v2
50+0=40+2v2
50-40=2v2
10=2v2
divide both sides by 2
v2=10/2
v2=5m/s
The pin's final velocity is 5m/s
<span>Assuming the car is travelling in the same direction for the entire hour, the acceleration is zero.</span>
A. 
The orbital speed of the clumps of matter around the black hole is equal to the ratio between the circumference of the orbit and the period of revolution:
where we have:
is the orbital speed
r is the orbital radius
is the orbital period
Solving for r, we find the distance of the clumps of matter from the centre of the black hole:
B. 
The gravitational force between the black hole and the clumps of matter provides the centripetal force that keeps the matter in circular motion:
where
m is the mass of the clumps of matter
G is the gravitational constant
M is the mass of the black hole
Solving the formula for M, we find the mass of the black hole:
and considering the value of the solar mass
the mass of the black hole as a multiple of our sun's mass is
C. 
The radius of the event horizon is equal to the Schwarzschild radius of the black hole, which is given by
where M is the mass of the black hole and c is the speed of light.
Substituting numbers into the formula, we find
<span>The scales is 1 m = 10 dm = 100 cm = 1000 mm. Then 10 dm equals 1000 mm and 1 dm equals 100 mm.The names of the measures in that scale are meter, decimeter, centimeter and milimiter. So, the answer is that the length that is 100 times larger than a milimieter is the decimeter (dm). </span>
