C. Oxide is a simple radical why??
1 answer:
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Answer:
One of each
Explanation:
Be is in Group 2, so it loses its two valence electrons in a reaction to form Be²⁺ ions.
Carbonate ion has the formula CO₃²⁻.
We can use the criss-cross method to work out the formula of beryllium carbonate.
The steps are
Write the symbols of the anion and cation.
Criss-cross the numbers of the charges to become the subscripts of the other ion.
Write the formula with the new subscripts.
Divide the subscripts by their highest common factor.
Omit all subscripts that are 1.
When you use this method with Be²⁺ and CO₃²⁻, you might be tempted to write the formula for the beryllium carbonate as Be₂(CO₃)₂
However, you can divide the subscripts by their largest common factor (2).
This gives you the formula Be₁(CO₃)₁.
We omit subscripts that are 1, so the correct formula is
BeCO₃
There is one Be²⁺ ion and one CO₃²⁻ ion in a formula unit of beryllium carbonate.
Answer:
The density is 3g/L
Explanation:
The reaction that occurs in the vessel is:
4 NH₃ + 5 O₂ → 4 NO + 6 H₂O
10,0g of NH₃ are:
6,50 g of O₂ are:
For a complete reaction of O₂ there are necessaries:
O₂ is limiting reactant. The excess moles of NH₃ are:
0,587 - 0,163 = <em>0,424 moles of NH₃</em>
These moles are:
<em>7,22g of NH₃</em>
Knowing O₂ is limiting reactant, mass of NO and H₂O are:
<em>4,87g of NO</em>
<em>4,39g of H₂O</em>
The total mass is: 7,22g + 4,87g + 4,39g = 16,48g ≡ <em>16,5g </em>
<em>-</em><em>The same mass add in the first. By matter conservation law-</em>
As vessel volume is 5,50L, density is:
16,5g/5,50L = <em>3g/L</em>
I hope it helps!