NaOH+HCl-> NaCl+H2O
1 mole of NaOH
1 mole of HCl.
To calculate volume of NaOH
CaVa/CbVb= Na/Nb
Where Ca=2M
Cb=1M
Va=200cm³
Vb=xcm³
Substitute into the equation.
2×200/1×Vb=1/1
400/Vb=1/1
Cross multiply
Vb×1=400×1
Vb=400cm³
To calculate the mass of sodium chloride, NaCl from the neutralization rxn.
Mole of NaCl=1
Molar mass of NaCl= 23+35.5=58.5
Mass=xgrammes.
Mass of NaCl=Number of moles × Molar mass.
Substitute
Mass of NaCl= 1×58.5
=58.5g
This is what I could come up with.
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Below are the choices that can be found elsewhere:
a. [CH3NH-] * [OH-] / [CH3NH3+]
<span>b. [CH3NH3+] / ([CH3NH2] * [OH-]) </span>
<span>c. [CH3NH3+] * [OH-] / [CH3NH2] </span>
<span>d. [CH3NH3+] * [OH-] / [CH3NH2] * [H2O]
</span>
The answer is C.
Answer:
Explanation:
Hello,
In this case, for the dissociation of the sodium hydroxide into sodium and hydroxyl ions we have:
Which is a 100% dissociation as sodium hydroxide is a strong base, therefore, the concentration of the hydroxyl ions are 1.0x10⁻⁹. For that reason, the pOH could be computed as:
Finally, from the definition of pH, we have:
Best regards.
Answer:
is that chromium on that computer ?
Explanation:
