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natka813 [3]
3 years ago
14

For the following amino acids, draw a triangle around the amine group, draw a square around the carboxyl and circle the side gro

up.

Chemistry
1 answer:
Agata [3.3K]3 years ago
4 0

Answer:

The answer to your question is:

Explanation:

See the picture below

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What type of bonds are formed between silicon(Si) and oxygen(O) in silicon dioxide (SiO2), a commonly component of sand?
Sladkaya [172]

Answer:

Silicone Dioxide

Explanation:

It is found on sand since ancient times and also a major component of glass..I have heard of a case when a lightning hit the sand and the sand actually turned into a somewhat glasslike figure

6 0
3 years ago
2. If a gas at 500 mL has a temperature of 45°C, then what is the new volume when the temperature is increased to 65°C? Show you
OLEGan [10]

Answer:

V2= 531.4 ml

Explanation:

T1= 273+45 °C= 318 Kelvin

T2= 273+65 °C= 338 Kelvin

V1= 500ml *( 0.001L/1ml)= 0.5 Liters

V2= \frac{V1 * T2}{T1}= \frac{0.5 L * 338K}{318K} = 0.5314465409 Liters* (1 ml/0.001 L)= 531.4 ml

8 0
3 years ago
(04.03 LC)
pishuonlain [190]
Carrying capacity, D
Emigration, C
Limiting factor, A
Population dynamics, B
4 0
3 years ago
Calculate the number of moles in 18.5 g of aluminum thiosulfate, Al2(S2O3)3
alisha [4.7K]

Answer:

0.05 mol

Explanation:

Moles = Mass / Mr (Relative formula mass)

Ar of aluminium = 27

Ar of sulphur = 32

Ar of oxygen = 16

Mr of Al2(S2O3)2 = (27×2)+((32×2)×3)+((16×3)×3)= 390

Moles = 18.5g / 390

Moles = 0.05 mol

5 0
3 years ago
In November 1987, a massive iceberg broke loose from the antartic ice mass and floated free in the ocean. The chunk of ice was e
il63 [147K]
<h2>Answer:</h2>

1.58  × 10∧16 pools.

<h3>Explanation:</h3>

Given:

Length of ice berg= 98 miles = 1557716 meters

Width of iceberg = 25 miles = 40233.6 meters

Thickness of iceberg = 750 ft = 230 meters

Volume of water in a swimming pool = 24,000 gallons = 90850 liters

The volume of the ice berg:

Volume = Length . width . thickness

Volume = 1557716 . 40233.6 . 230 = 1,441, 468, 016, 5248 m3 =  1,441, 468, 016, 5248 × 10 ∧3 L.

1 pool contains liters of water:  90850 liters

1,441, 468, 016, 5248 × 10 ∧3 liters contains = 1/90850 . 1,441, 468, 016, 524.8 × 10 ∧3 .

= 1.100 .  1,441, 468, 016, 5248 × 10 ∧3 L.

= 1.58  × 10∧16 pools.

Hence 1.6 × 10∧16 pools will be filled with that chunk of ice.


4 0
3 years ago
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