Sodium is Highly reactive. It reacts with like everything
The most stable conformation of
trans-1-tert-butyl-2-methylcyclohexane is the one in which both the
tert-butyl group and the methyl group are located near the equatorial position.
Trans conformation are usually stable at the equatorial position to avoid the
bulkyl group ( the tert-butyl group and methyl group) be together to reduce the
so called Steric hindrance.
<span>When 1 mol of glucose is burned, 2802.5 KJ of energy is released.
</span>
Answer:
a) mass flow = 56940 Kg/h
b) mass flow = 202.5 mol/s
Explanation:
∴ δ C6H6 = 876 Kg/m³,,,,,wwwcarlroth.com
⇒ 65m³/h * 876 Kg/m³ = 56940 Kg/h
⇒ 56940 Kg/h * ( 1000 g/Kg ) * ( mol/ 78.11 g) * ( h/3600s )= 202.5 mol/s
Here we have to draw the major product in the acid catalysed hydration reaction of 4-ethyl-3,3-dimethyl-1-hexene.
The 4-ethyl-3,3-dimethyl-1-hexene converts to 2-hydroxy-4-ethyl-3,3-dimethyl-1-hexane as a major product by acid catalyzed hydration reaction.
The acid catalyzed hydration of an alkene is the Sn¹ reaction. Where in the first step a carbocation is generated. The stability of the carbocation depends upon the position of the neighboring group having +I inductive effect.
In the next step the water molecule attack the carbocation and the corresponding alcohol is produced.
In 4-ethyl-3,3-dimethyl-1-hexene the carbocation formed in the C₂ position which is more stable than the C₁ position due to presence of the dimethyl and ethyl group in the neighboring position which have strong +I inductive effect. This is absence in C₁ position.
In the next step the water molecule attack the C₂ position to form the alcohol.
4-ethyl-3,3-dimethyl-1-hexene converts to 2-hydroxy-4-ethyl-3,3-dimethyl-1-hexane by acid catalyzed hydration reaction which is the major product along with 1-hydroxy-4-ethyl-3,3-dimethyl-1-hexane as a minor product.
The reaction mechanism is shown in the image.