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ser-zykov [4K]
3 years ago
12

Which force requires contact?

Physics
2 answers:
Minchanka [31]3 years ago
8 0

Answer:

A

Explanation: A is a example of Air resistance force, which is a contact force.

rosijanka [135]3 years ago
6 0
Answer is A. The force exerted by air as an object moves through it.
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Gases tend to deviate from the ideal gas law at
IgorLugansk [536]
<h2>Answer: high pressures</h2>

The Ideal Gas equation is:

P.V=n.R.T  

Where:

P is the pressure of the gas

n the number of moles of gas

R=0.0821\frac{L.atm}{mol.K} is the gas constant

T is the absolute temperature of the gas in Kelvin.  

According to this law, molecules in gaseous state do not exert any force among them (attraction or repulsion) and the volume of these molecules is small, therefore negligible in comparison with the volume of the container that contains them.

Now, real gases can behave approximately to an ideal gas, under the conditions described above.

However, when <u>temperature is low</u> these gases deviate from the  ideal gas behavior, because the molecules move slowly, allowing the repulsion or attraction forces to take effect.

The same happens at <u>high pressures</u>, because the volume of molecules is no longer negligible.

5 0
4 years ago
Suppose we take a 1 m long uniform bar and support it at the 21 cm mark. Hanging a 0.40 kg mass on the short end of the beam res
Ipatiy [6.2K]

Answer:

The mass of the beam is = 29 kg.

Explanation:

A beam with mass 40 kg is shown in figure. Point S is the support point. Point B is the middle point on the beam where mass of the beam acts.

Taking moment about Point S

40 × 21 = M_{beam} × 29

M_{beam} = 29 kg

Therefore the mass of the beam is = 29 kg.

4 0
3 years ago
10. Find the mass density of a ball with 22.0 g and a radius of 0.875 cm.
Ede4ka [16]

Answer:

Mass (m) = 22.0 g

Radius (r) = 0.875 cm

Density (d) = ?

First find ( volume) ;

v =  \frac{4}{3} \pi \:  {r}^{3}  \\  \\ v =  \frac{4}{3}  \times 3.14 \times ( {0.875)}^{3}  \\  \\ v =  \frac{4}{3}   \times 3.14 \times 0.66992187  \:  {cm}^{3} \\  \\ v = 2.8 \:  {cm}^{3}

Density =  \frac{mass}{volume}  \\  \\ d =  \frac{m}{v}  \\  \\ d =  \frac{22}{2.8}  \\  \\ d = 7.857 \:  \frac{g}{ {cm}^{3} }

I hope I helped you^_^

7 0
3 years ago
You are standing in an elevator that is accelerating upward at 1m/s². Which of the following pairs of forces is an action-reacti
Lostsunrise [7]

Answer:

B The force that the floor of the elevator exerts on you and the force that you exert on the floor of the elevator

Explanation:

A. is incorrect because the force of gravity on you will always stays the same while the force of the elevator exerts on you changes as it takes you upward

B. is correct in accordance to Newton's 3rd law of action and reaction forces.

C. is incorrect because gravity force stays the same while the force that you exerts on the floor change as elevator moving upward.

D. is incorrect although it states Newton's 1st law. However there can still be pair of forces (part B) that could counter balance each other among other forces.

5 0
3 years ago
The object experiences two external forces: 60 N to the west and 130 N to the east. What is the net external force?
MArishka [77]

Answer: 70 N to the East

Explanation:

lets assume east is positive and west is negative, since they are in opposite directions the net external force = F1+F2

Net force = (-60) + 130

Net force = 70

or

Net force = 70 N in the east direction

4 0
3 years ago
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