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vagabundo [1.1K]
3 years ago
5

When you push downward on a book at rest on a table, you feel an upward force. Does this force depend on friction? Defend your a

nswer.
Physics
1 answer:
777dan777 [17]3 years ago
7 0

Answer:

No

Explanation:

We can explain the upward force in terms of Newton's third law, which states:

"when an object A exerts a force (action) on object B, then object B exerts an equal and opposite force (reaction) on object A"

If we apply this law to the situation described in the problem, the push you apply downward is the action, while the upward force exerted by the book on you is the reaction.

This reaction does not depend on the friction. In fact, friction acts whenever you try to move an object along a surface, in a direction parallel to the surface itself. In this case, instead, you are trying to push the object perpendicularly to the surface, not parallel: so, no friction acts when you push. The reaction force is mainly due to the normal reaction of the table on the book, that "pushes" the book upward, balancing the downward force and keeping the book at rest.

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fredd [130]
C.energy
The law of conservation of energy says that energy can neither be created nor destroyed.
6 0
3 years ago
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If a force of 1.0 N pulled up and parallel to the surface of the incline is required to raise the mass back to the top of the in
wel

The question is incomplete! The complete question along with answer and explanation is provided below.

Question:

A 0.5 kg mass moves 40 centimeters up the incline shown in the figure below. The vertical height of the incline is 7 centimeters.

What is the change in the potential energy (in Joules) of the mass as it goes up the incline?  

If a force of 1.0 N pulled up and parallel to the surface of the incline is required to raise the mass back to the top of the incline, how much work is done by that force?

Given Information:  

Mass = m = 0.5 kg

Horizontal distance = d = 40 cm = 0.4 m

Vertical distance = h = 7 cm = 0.07 m

Normal force = Fn = 1 N

Required Information:  

Potential energy = PE = ?

Work done = W = ?

Answer:

Potential energy = 0.343 Joules

Work done = 0.39 N.m

Explanation:

The potential energy is given by

PE = mgh

where m is the mass of the object, h is the vertical distance and g is the gravitational acceleration.

PE = 0.5*9.8*0.07

PE = 0.343 Joules

As you can see in the attached image

sinθ = opposite/hypotenuse

sinθ = 0.07/0.4

θ = sin⁻¹(0.07/0.4)

θ = 10.078°

The horizontal component of the normal force is given by

Fx = Fncos(θ)

Fx = 1*cos(10.078)

Fx = 0.984 N

Work done is given by

W = Fxd

where d is the horizontal distance

W = 0.984*0.4

W = 0.39 N.m

3 0
3 years ago
Can someone please explain number 8?
guajiro [1.7K]

Answer: Ax=(Vx-Vox)/(T)

Vx=Vox+Ax*T

Solving for Ax in terms of Vx, Vox, T

Vx-Vox=Ax*t

Ax=(Vx-Vox)/(T)

This is saying the acceleration in the x-direction can be found by taking the difference between the finial and initial Velocity in x-direction and dividing it by the Total Time.

Any questions please feel free to ask. Thanks

8 0
3 years ago
What is the speed of a car that travels 48 km in 2 hours?
ankoles [38]
Speed=distance/time

distance =48km
time=2 hours

speed=48/2
=24km/h


speed=24km/h

FORMULAS

speed = distance/time
time = distance/speed
distance = speed×time

3 0
3 years ago
A crow is flying horizontally with a constant speed of 2.70 m/s when it releases a clam from its beak. the clam lands on the roc
vovangra [49]

Part a)

in horizontal direction there is no gravity or no other acceleration

so in horizontal direction the speed of clam will remain same

v_x = 2.70 m/s

Part b)

In vertical direction we can use kinematics

v_f = v_i + at

v_f = 0 + 2.1 * 9.8

v_f = 20.6 m/s

part c)

if the speed of crow will be increased then the horizontal speed of the clam will also increase but there is no change in the vertical speed

5 0
3 years ago
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