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vagabundo [1.1K]
3 years ago
5

When you push downward on a book at rest on a table, you feel an upward force. Does this force depend on friction? Defend your a

nswer.
Physics
1 answer:
777dan777 [17]3 years ago
7 0

Answer:

No

Explanation:

We can explain the upward force in terms of Newton's third law, which states:

"when an object A exerts a force (action) on object B, then object B exerts an equal and opposite force (reaction) on object A"

If we apply this law to the situation described in the problem, the push you apply downward is the action, while the upward force exerted by the book on you is the reaction.

This reaction does not depend on the friction. In fact, friction acts whenever you try to move an object along a surface, in a direction parallel to the surface itself. In this case, instead, you are trying to push the object perpendicularly to the surface, not parallel: so, no friction acts when you push. The reaction force is mainly due to the normal reaction of the table on the book, that "pushes" the book upward, balancing the downward force and keeping the book at rest.

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How are wave properties and energy related?<br> EXPLAIN
dexar [7]

Answer:

The higher the amplitude, the higher the energy. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

6 0
2 years ago
QUESTION 10
Elena L [17]

The maximum value of θ of such the ropes (with a maximum tension of 5,479 N) will be able to support the beam without snapping is:

\theta =37.01^{\circ}

We can apply the first Newton's law in x and y-direction.

If we do a free body diagram of the system we will have:

x-direction

All the forces acting in this direction are:

T_{1}sin(\theta)-T_{2}sin(\theta)=0    (1)

Where:

  • T(1) is the tension due to the rope 1
  • T(2) is the tension due to the rope 2

Here we just conclude that T(1) = T(2)

y-direction

The forces in this direction are:

T_{1}cos(\theta)+T_{2}cos(\theta)-W=0   (2)

Here W is the weight of the steel beam.

We equal it to zero because we need to find the maximum angle at which the ropes will be able to support the beam without snapping.

Knowing that T(1) = T(2) and W = mg, we have:

T_{1}cos(\theta)+T_{1}cos(\theta)-m_{steel}g=0

2T_{1}cos(\theta)-m_{steel}g=0

2T_{1}cos(\theta)=m_{steel}g

T(1) must be equal to 5479 N, so we have:

cos(\theta)=\frac{m_{steel}g}{2T_{1}}

cos(\theta)=\frac{892*9.81}{2*5479}

cos(\theta)=\frac{892*9.81}{2*5479}

cos(\theta)=0.80

Therefore, the maximum angle allowed is θ = 37.01°.

You can learn more about tension here:

brainly.com/question/12797227

I hope it helps you!

8 0
3 years ago
Write any two importance of gravitational force​
saul85 [17]

Answer:

plz mark me as brainliest plz

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The gravitational force of the earth keeps us bound to the earth. Gravitational force between earth and sun makes the earth move around the sun. Gravitational force between moon and earth makes the moon go around the earth.

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Potential energy becomes kinetic energy when:
Sedbober [7]

Answer:

An object has potential energy (stored energy) when it is not in motion. Once a force has been applied or it begins to move the potential energy changes to kinetic energy (energy of motion).

EXAMPLE: A rock sitting on the edge of a cliff. If the rock falls, the potential energy will be converted to kinetic energy, as the rock will be moving. A stretched elastic string in a longbow.

5 0
2 years ago
9. How does the length of the hypotenuse in a right triangle relate to the lengths of the legs? (2 points)
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3 years ago
Read 2 more answers
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