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Kay [80]
3 years ago
10

What happens in a cloud to cause electrons to move from some particles to others?

Physics
1 answer:
vova2212 [387]3 years ago
6 0

Answer:

Air molecules and suspended water droplets collide as they swirl around in the clouds. Warmer air and water droplets rise, carrying charges with them. The result is an excess of positive charge near the cloud tops, and an excess of negative charge in the bottom layers of the clouds.

they are knocked off some ice and added to other ice as they crash past each other

Explanation:

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Newton's second law is a major part of mechanics. However, it does have its limitations. Under what condition does the second la
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It a major part of mechanics what do you think.

Explanation:

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Calculate the density of the baseball. Use the formula D = m/V where D is the density, m is the mass, and V is the volume. Deter
garik1379 [7]

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Explanation:

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A short current element dl⃗ = (0.500 mm)j^ carries a current of 4.80 A in the same direction as dl⃗ . Point P is located at r⃗ =
sammy [17]

Answer:

Magnetic field in Tesla: 1.65*10^−10 T,   0,   3.09*10^−10 T

Explanation:

Given data:

i = 4.8 A ,

dBx = 1.65*10^-10 T

dBy = 0 T

dBz = 3.09 * 10^-10 T

Attached below is the detailed solution

7 0
3 years ago
Mention a few precautions to be taken at the time of spraying the pesticides
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3 0
3 years ago
1) A car accelerates uniformly from rest and reaches a speed of 19.8 m/s in 7 s. The diameter of a tire is 38.5 cm. Find the num
andre [41]

Answer:

1) 57 revolutions.

2) 4.52 m

3) 1531.2 m

Explanation:

Question 1:

Given:

Initial velocity, u = 0

Final velocity, v = 19.8\ m/s

Time, t = 7\ s

Acceleration, a = \frac{\textrm{Final velocity-Initial velocity}}{Time}=\frac{19.8}{7}=2.83\ m/s^2

Now, displacement of the tire is given as:

S=ut+\frac{a}{2}t^2\\S=0+\frac{2.83}{2}7^2=69.335\ m

Displacement of tire in 1 revolution is equal to its circumference.

Therefore, displacement in 1 revolution = \pi\times(Diameter)=\pi \times 38.5\times 10^{-2}=1.2095\ m

Now, number of revolutions is given as:

N=\frac{Total\ displacement}{Displacement\ per\ revolution}\\N=\frac{69.335}{1.2095}=57

Therefore, the number of revolutions are 57.

Question 2:

Given:

Radius of the wheel is, R=4.8\ m

Angle of rotation is, \theta=54°

Converting degree to radians, we get:

\theta=54\times \frac{\pi}{180}=0.3\pi

Now, path length is given as:

L=R\theta=(4.8)(0.3\pi)=1531.2\ m

Therefore, the path length of a point on the wheel is 4.52 m

Question 3:

Radius of the wheel is, R=4.8\ m

Angle of rotation is, \theta=319 radians

Now, path length is given as:

L=R\theta=(4.8)(319)=4.52\ m

Therefore, the path length of a point on the wheel is 1531.2 m.

7 0
3 years ago
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