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2 years ago

What happens in a cloud to cause electrons to move from some particles to others?

Physics

1 answer:

vova2212 [387]2 years ago

6 0

Answer:

Air molecules and suspended water droplets collide as they swirl around in the clouds. Warmer air and water droplets rise, carrying charges with them. The result is an excess of positive charge near the cloud tops, and an excess of negative charge in the bottom layers of the clouds.

they are knocked off some ice and added to other ice as they crash past each other

Explanation:

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Why can populations share a habitat but not a niche?

ELEN [110]

Because <span>two organisms with exactly the same </span>niche can't survive in the samehabitat<span> (because they compete for exactly the same resources, so one </span>will<span> drive the other to extinction). However, species whose </span>niches<span> only partly overlap may be able to coexist.</span>

4 0

3 years ago

An iron anchor of density 7850.00 kg/m3 appears 183 N lighter in water than in air.

andrew11 [14]

<h2>a) Volume of anchor is 0.019 m³</h2><h2>b) Weight of anchor in air is 1463.17 N</h2>

Explanation:

a) Weight loss in water = Volume of object x density of water x acceleration due to gravity

183 = Volume of anchor x 1000 x 9.81

Volume of anchor = 0.019 m³

b) Weight = Mass x acceleration due to gravity = Volume x Density x acceleration due to gravity

Weight of anchor in air = Volume of anchor x Density of anchor x acceleration due to gravity

Weight of anchor in air = 0.019 x 7850 x 9.81 = 1463.17 N

Weight of anchor in air = 1463.17 N

3 0

3 years ago

A 1550 kg car located at < 319, 0, 0 > m has a momentum of < 45000, 0, 0 > kg·m/s. What is its location 10 s later?

Serggg [28]

Answer:

< 45319, 0, 0 > m

Explanation:

mass, m = 1550 kg

r = < 319, 0, 0 > m

v = < 4500, 0, 0 > m/s

t = 10 s

distance traveled in 10 second is

d = v x t

d = < 4500 x 10, 0 x 10, 0 x 10 > m

d = < 45000, 0, 0 > m

So, the new location of the car is

r' = r + d = < 319, 0, 0 > + < 45000, 0, 0 >

r' = < 45319, 0, 0 > m

5 0

3 years ago

A conservative force F⃗ is in the +x-direction and has magnitude F(x)=α/(x+x0)2, where α=0.800N.m2 and x0=0.200m. (a) What is th

sashaice [31]

Answer:

U=α/(x+x_0)^2

v=1.88m/s

Explanation:

We have that

$F(x)=\frac{\alpha}{(x+x_0)^2}\\\alpha=0.800Nm^2\\x_0=0.200m$

(a)

The potential is calculated by using

$U=-\int Fdx=-\int \frac{\alpha}{(x+x_0)^2}dx\\U=\frac{\alpha}{(x+x_0)}$

(b)

m=0.5kg

The acceleration can be obtained if we calculate the force for x=4, and after we compute the acceleration

$F(0.4)=\frac{0.8Nm^2}{(0.4m+0.2m)^2}=2.22N\\F=ma\\2.22N=(0.5kg)a\\a=4.44\frac{m}{s^2}$

and finally, we can use the equation for the final speed

$v^2=v_0^2+2ax\\\\v=\sqrt{(0)+2(4.44\frac{m}{s^2})(0.4m)}\\\\v=1.88\frac{m}{s}$

I hope this is useful for you

regards

5 0

3 years ago

Which is a “big idea” for matter and change

Agata [3.3K]

I think it is number 3 hope it helps

5 0

3 years ago

Read 2 more answers