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Lynna [10]
3 years ago
10

What can a drop of liquid mercury be described as?

Chemistry
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer:

a pure substance and an element

Explanation:

A drop of liquid mercury be described as a pure substance and an element.

Mercury is one of the known elements in the periodic table. The drop of liquid mercury is pure since it has constant and definite composition as well as distinct chemical properties.

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To learn more about the genetic material of plant and animal cells, where would a person look?
Agata [3.3K]
The person would look B) in the nucleus.

Hope this helps!

-Payshence xoxo
6 0
3 years ago
Consider the electron configuration. A box holds an up and a down arrow. A box holds an up and a down arrow. A box holds an up a
icang [17]

Answer:

Chlorine

Explanation:

Each arrow represents one electron. Most of the boxes are filled, meaning they have two electrons. The last box only has one arrow, so it only has one electron. If you add it up, you get 17, which is Chlorine.

8 0
3 years ago
Read 2 more answers
Sulfur reacts with fluorine to produce three different compounds. The mass ratio of fluorine to sulfur for each compound is give
NARA [144]

Answer:

Explanation:

Mass of F / Mass of S = 2.962/1 =2.962 X 32 / 32 = 94.78/32

Mass of F / Mass of S = 2.370 /1 = 2.370 X 32 / 32 = 75.84 /32

Mass of F /Mass of S = 3.555/1 = 3.555 x 32 / 32 = 113.76 / 32 .

Now constant mass of S that is 32 g reacts with different mass of F. They are as follows :

94.78 g , 75.84 g , and 113.76 g

Their ratio = 94.78 : 75.84 : 113.76

divide them by 19

their ratio = 5 : 4 : 6

So these data are consistent with law of multiple proportion.

8 0
3 years ago
When 4.41g of phosphoric acid (H3PO4) react with 9.25g of barium hydroxide, water and insoluble barium phosphate form. [T/I-7] a
AnnZ [28]

Answer:

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

Explanation:

Let's consider the unbalanced equation that occurs when phosphoric acid reacts with barium hydroxide to form water and barium phosphate. This is a neutralization reaction.

H₃PO₄(aq) + Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

We will balance it using the trial and error method.

First, we will balance Ba atoms by multiplying Ba(OH)₂ by 3 and P atoms by multiplying H₃PO₄ by 2.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

Finally, we will get the balanced equation by multiplying H₂O by 6.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

3 0
3 years ago
what is the pH of a solution prepared from solid, neutral 2-nitrophenol providing a fromal concentration of 0.0353M, given that
REY [17]

Answer:

pH = 4.34

Explanation:

pH= -1/2(logKa) -1/2(log C)

= -1/2( log 5.98*10^-8) -1/2(log 0.0353)

=-1/2(-7.22)-1/2(-1.45)

=3.61+0.725= 4.34

7 0
3 years ago
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