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2 years ago

What is the compound name of O2CI4?

Chemistry

1 answer:

Dafna1 [17]2 years ago

6 0

Answer:

Dioxide tetrachloride

Explanation:

Di meaning 2 as in o2 and tetra the Greek numerical for 4 attached to chlorine in a group it is Chloride.

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Which best explains the relationship between parent rock and soil<br><br> composition?

irina1246 [14]

<span>Soil is partially the result of the physical and chemical weathering of its parent rock. The minerals found in the soil were either in that parent rock, or they were formed from the weathering products of the parent rock.</span>

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2 years ago

How many moles are in a 111.5 gram sample of sodium chloride, NaCl?

Katarina [22]

Answer: 1.91 moles

Explanation:

First you want to find the molar mass of NaCL

Na = 22.99g Cl = 35.45g

22.99g + 35.45g = 54.44g

Then divide 111.5g by 54.44g and this will give you moles.

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2 years ago

Water is being pumped from the bottom of a well 150 feet deep at a rate of 200 gal/hour into a vented storage tank 30 feet above

KengaRu [80]

Explanation:

As the given data is as follows.

Height, H = 150 feet

Heat gain = 30,000 BTU/hr, and Heat loss = 25000 BTU/hr

m = mass of water heated = 700 gallons = 5810 lbs

$C_{p}$ is the heat capacity of water = 1 BTU/lb $^{o}F$ (given)

$\Delta T$ = temperature difference = $120^{o}F - 35^{o}F$

Heat energy required to heat 700 gal can be calculated as follows:

Heat Required = $5810 lbs \times 1 BTU/lb^{o}F \times (120^{o}F - 35^{o}F)$

Thus, water rises till $120^{o}F$ .

3 0

3 years ago

Why will no one help this is bogus

Soloha48 [4]

Answer:

Explanation:

3 0

3 years ago

Read 2 more answers

A 7.00-mL portion of 8.00 M stock solution is to be diluted to 0.800 M. What will be the final volume after dilution? Enter your

amm1812

Explanation:

The number of moles of solute present in liter of solution is defined as molarity.

Mathematically, Molarity = $\frac{\text{no. of moles}}{\text{Volume in liter}}$

Also, when number of moles are equal in a solution then the formula will be as follows.

$M_{1} \times V_{1} = M_{2} \times V_{2}$

It is given that $M_{1}$ is 8.00 M, $V_{1}$ is 7.00 mL, and $M_{2}$ is 0.80 M.

Hence, calculate the value of $V_{2}$ using above formula as follows.

$M_{1} \times V_{1} = M_{2} \times V_{2}$

$8.00 M \times 7.00 mL = 0.80 M \times V_{2}$

$V_{2} = \frac{56 M. mL}{0.80 M}$

= 70 ml

Thus, we can conclude that the volume after dilution is 70 ml.

7 0

3 years ago