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Setler [38]
3 years ago
6

Iron has more mass than gold. Does this mean that the density of iron is greater

Physics
2 answers:
Strike441 [17]3 years ago
6 0

Answer:

There masses are identical "I hope this helps"

kicyunya [14]3 years ago
3 0
I think it does mean that yeah
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If a battery causes a wire to carry a current of 4 Amps how many coulombs of charge flow past any point in the wire in 3 seconds
BabaBlast [244]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

According to above question ~

  • Current (I) = 4 Amperes

  • Time (t) = 3 seconds

  • Charge (q) = ?

Let's find the charge (q) by using formula ~

  • I =  \dfrac{q}{t}

  • 4 =  \dfrac{q}{3}

  • q = 4 \times 3

  • q = 12 \:  \: coulombs

Hence, 12 coulombs of charge flow past any point in the wire in 3 seconds

7 0
3 years ago
16x^2y^2-25a^2b^2<br>factorize the expression​
SIZIF [17.4K]

Answer:

(4xy+5ab)(4xy-5ab)

Explanation:

16x^{2}y^{2}-25a^{2}b^{2}

4^2 is 16 and 5^2 is 25,

Also, (x-a)(x+a) = x^2-a^2

So, this factorized is:

(4xy+5ab)(4xy-5ab)

Hope this helps!

8 0
2 years ago
Which best describes two counteracting forces on an object
Natali5045456 [20]

The correct answer is B two children pulling apart a wishbone

Let me know if you have any questions, and have a nice day!

6 0
3 years ago
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The temperature of a balloon is lowered with liquid nitrogen. The balloon appears to deflate because the A. nitrogen has burst t
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The temperature of a balloon is lowered with liquid nitrogen. The balloon appears to deflate because the gas in the balloon lost energy and condensed. The answer is letter D.

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3 years ago
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Here the block has two work done on it

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2. Work done by friction force

So here it start from height "h" and then again raise to height hA after compressing the spring

So work done by the gravity is given as

W_g = m_A g(h - h_A)

Now work done by the friction force is to be calculated by finding total path length because friction force is a non conservative force and its work depends on total path

W_f = -(\mu m_A g cos\theta)(\frac{h}{sin\theta} + \frac{h_A}{sin\theta})

W_f = -\mu m_A g cot\theta(h + h_A)

Total work done on it

W = m_A g(h - h_A) - \mu m_A g cot\theta(h + h_A)

So answer will be

None of these

7 0
3 years ago
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